All categories

3 years ago

Simplify (10–2) 4. A) 10^-8 B)10^-6 C)-10^-6 D)-10^8

Mathematics

2 answers:

Hatshy [7]3 years ago

8 0

Answer:

Step-by-step explanation:

$(10^{-2})^{4}$

Apply the law of exponents.

$10^{-2 \times 4}$

$=10^{-8}$

ololo11 [35]3 years ago

5 0

Answer:

$= {10}^{ - 8} \\$

Answer A is correct.

Step-by-step explanation:

${( {10}^{ - 2}) }^{4} \\ {10}^{ - 2 \times 4} \\ = {10}^{ - 8}$

You might be interested in

Find the global maximum and global minimum values (if they exist) of x 2 + y 2 in the region x + y = 1. If there is no global ma

Grace [21]

Given that $x+y=1$ , we have $y=1-x$ , so that

$f(x,y)=x^2+y^2\iff g(x)=x^2+(1-x)^2$

Take the derivative and find the critical points of $g$ :

$g'(x)=2x-2(1-x)=4x-2=0\implies x=\dfrac12$

Take the second derivative and evaluate it at the critical point:

$g''(x)=4>0$

Since $g''$ is positive for all $x$ , the critical point is a minimum.

At the critical point, we get the minimum value $g\left(\frac12\right)=f\left(\frac12,\frac12\right)=\frac12$ .

5 0

3 years ago

One bushel of apples weighs 22<br> kilograms. How many kilograms<br> do 5.7 bushels weigh?

Solnce55 [7]

Answer:

125.4 kg

Step-by-step explanation:

I attached a picture of my work and I stuck it into my calculator to check it

5 0

3 years ago

A line includes the points (0,2) and (1,6).

trasher [3.6K]

Y=4x+2. To get slope you use 6-2/1-0. Which gives you 4. You then put that in point slope form.

6 0

2 years ago

5. A flock of geese flies 50 miles per hour. Write a linear

MrMuchimi

Answer:

y=50x+0

Step-by-step explanation:

y=mx+b is y-intercept form

I will make x= hours and y= distance (miles)

every 1 you add to x has to represent 50 miles

for the y intercept, it was unspecified so I assumed 0

Hope this helps :)

7 0

2 years ago

Read 2 more answers

Solve quadratic formulax^2-4x+3=0

bekas [8.4K]

The general formula for a equation of the form:

$ax^2+bx+c=0$

is:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

$\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}$

then:

$x_1=\frac{4+2}{2}=\frac{6}{2}=3$

and

$x_2=\frac{4-2}{2}=\frac{2}{2}=1$

Therefore, x=3 or x=1.

8 0

9 months ago