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yarga [219]
3 years ago
10

Simplify (10–2) 4. A) 10^-8 B)10^-6 C)-10^-6 D)-10^8

Mathematics
2 answers:
Hatshy [7]3 years ago
8 0

Answer:

A

Step-by-step explanation:

(10^{-2})^{4}

Apply the law of exponents.

10^{-2 \times 4}

=10^{-8}

ololo11 [35]3 years ago
5 0

Answer:

= {10}^{ - 8}  \\

Answer A is correct.

Step-by-step explanation:

{( {10}^{ - 2}) }^{4}  \\  {10}^{ - 2 \times 4}  \\   = {10}^{ - 8}

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If f(x)=3x^2-2 and g(x)=4x+2, what is the value of (f+g)(2)
elena-14-01-66 [18.8K]

(f+g)(x)=3x^2-2+4x+2=3x^2+4x\\\\(f+g)(2)=3\cdot2^2+4\cdot2=12+8=20

5 0
3 years ago
Write y=x - 5 in standard form
Vilka [71]

Answer:x

− y = 5 x-y=5


Step-by-step explanation:


4 0
3 years ago
Patrick can learn 42 blessings in 6 hours. At that rate, how many blessings can he learn in 9 hours?
Vladimir [108]

divide 42 by 6 and get 7 so mulyiply 7 by 9

8 0
2 years ago
Which statements describe the figure on the grid if each square has side lengths of 1 cm? Check all that apply. On a coordinate
PolarNik [594]

The figure on the grid is an illustration of areas and perimeters of a shape

<h3>How to determine the true statements?</h3>

The question is incomplete, as the figure is not given.

So, I will provide a general explanation on how to determine the area and the perimeter of a shape.

The area of a shape is the amount of space on that shape.

Take for instance a square that has a side length 5 units.

The area of the square would be:

Area = 5 * 5 = 25 square units

On the other hand, the perimeter is the sum of the side lengths of the shape.

Using the same square that has a side length 5 units.

The perimeter of the square would be:

Perimeter = 4 * 5 = 20 units

Read more about area and perimeter at:

brainly.com/question/19819849

#SPJ1

3 0
2 years ago
Joe wants to enlarge the rectangular pumpkin patch located on his farm. The pumpkin patch is currently 40 meters wide and 60 met
vodomira [7]

Answer:

15x^2+380x+2400

The diagram is shown below for reference.

Step-by-step explanation:

We are given the length and width of old pumpkin patch as 60 meters and 40 meters respectively.

It further says length is increased by 5x meters and width increased by 5x meters.

So the length of the new pumpkin patch would be 60+5x meters.

And the width would be 40+3x meters.

We know area of a rectangular shape =length \times width

So, plugging the above values, we get the area of the new pumpkin patch as:

=(60+5x)\times (40+3x)\\=2400+180x+200x+15x^2\\=2400+380x+15x^2\\=15x^2+380x+2400 on rearranging.

Thus the function of the area of the new pumpkin patch would be:

f(x) = 15x^2+380x+2400

5 0
3 years ago
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