Question 6

Help please with this question?

Aliun [14]

36/39 or 12/13 is th answer to that

4 0

3 years ago

Read 2 more answers

Solve<br> log4 (x+3)- log4 (x+2)≥3/2<br> Please help

mart [117]

Https://web2.0calc.com/ try this or

this http://rational-equations.com/in-rational-equations/graphing-equations/distributive-property-simplif...
they are math calculator..... hope this helps

4 0

3 years ago

At a military function, three cannons are fired at intervals of 12

Morgarella [4.7K]

Answer:

144 seconds

Step-by-step explanation:

To do solve this question, we must find the LCM (least common multiple) of 12, 16, and 18.

Let's start by prime factorizing (finding the prime factors) all the numbers.

$12\rightarrow3*4\rightarrow2*2*3$

$16\rightarrow4*4\rightarrow2*2*2*2$

$18\rightarrow2*9\rightarrow2*3*3$

Now, we must find the greatest quantity of each [prime] number and multiply them together to obtain the least common multiple.

Upon further evaluation of the [prime] factors, we can see that we need four 2s and two 3s. Therefore...

$2*2*2*2*3*3=2^4*3^2=16*9=144$

They will be fired together again after 144 seconds.

3 0

3 years ago

A delivery truck travels 55 miles per hour. How many feet per hour is Mr. Jones driving?

Irina-Kira [14]

Answer:

A delivery truck, Mr. Jones drives 290400 feet per hour.

Step-by-step explanation:

To Determine:

How many feet per hour is Mr. Jones driving?

Solution Steps:

A delivery truck travels 55 miles per hour.

As we know that

Total number of feet in one mile = 5,280

so

Total number of feet in 55 miles = 5,280 × 55 = 290400

Thus

A delivery truck travels 290400 feet per hour.

Therefore, a delivery truck, Mr. Jones drives 290400 feet per hour.

3 0

3 years ago

Suppose that the warranty cost of defective widgets is such that their proportion should not exceed 5% for the production to be

Vedmedyk [2.9K]

Answer: 63 defective widgets

Step-by-step explanation:

Given that the proportion should not exceed 5%, that is:

p< or = 5%.

So we take p = 5% = 0.05

q = 1 - 0.05 = 0.095

Where q is the proportion of non-defective

We need to calculate the standard error (standard deviation)

S = √pq/n

Where n = 1024

S = √(0.05 × 0.095)/1024

S = 0.00681

Since production is to maximize profit(profitable), we need to minimize the number of defective items. So we find the limit of defective product to make this possible using the Upper Class Limit.

UCL = p + Za/2(n-1) × S

Where a is alpha of confidence interval = 100 -90 = 10%

a/2 = 5% = 0.05

UCL = p + Z (0.05) × 0.00681

Z(0.05) is read on the t-distribution table at (n-1) degree of freedom, which is at infinity since 1023 = n-1 is large.

Z a/2 = 1.64

UCL = 0.05 + 1.64 × 0.00681

UCL = 0.0612

Since the UCL in this case is a measure of proportion of defective widgets

Maximum defective widgets = 0.0612 ×1024 = 63

Alternatively

UCL = p + 3√pq/n

= 0.05 + 3(0.00681)

= 0.05 + 0.02043 = 0.07043

UCL =0.07043

Max. Number of widgets = 0.07043 × 1024

= 72

7 0

3 years ago