Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
To start with, 76 is 80% of 95. (76/95=0.8)
This means that we take the difference from 100% of 95 and 80% of 95, and get a 20% decrease.
Answer:
10
Step-by-step explanation:
subtract 5y from both sides of the equation
The second box to the left side
Enlarging by 1.5 will make the lengths 12' and 6'. Area is L*W. 12*6=72
<span>72'^2</span>
