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anyanavicka [17]
3 years ago
12

there are 10 marbels in a bag, 4 are multi colored and 6 are solid. what is the probability of picking a solid marble and then a

nother solid marble without replacing the first marble?​
Mathematics
2 answers:
jonny [76]3 years ago
8 0

Answer:

(2/5) * (3/4) = 3/10 = 0.3

Mnenie [13.5K]3 years ago
4 0

Answer:

55% probability

Step-by-step explanation:

You might be interested in
3/4(8x + 20) - 4x > -11
den301095 [7]

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

3/4(8x + 20) - 4x > -11​

x ==> ?

Step 02:

Inequality :

\begin{gathered} \frac{3}{4}\cdot(8x\text{ + 20) - 4x > -11} \\ 6x\text{ + }15\text{ -4x > -11} \end{gathered}

2x + 15 > -11

2x + 15 - 15 > -11 - 15

2x > - 26

2x / 2 > -26 / 2

x > - 13

The answer is:

x > -13

7 0
1 year ago
Two trucks started toward each other at the same time from towns 500 km apart. One truck traveled at a rate of 65 km per hour wh
vredina [299]
They will meet in 4 hours.
7 0
3 years ago
Hudson is already 40 miles away from home on his way back to college.
Zarrin [17]
What's the question?
4 0
4 years ago
What 3 numbers can you times to get 9
Masja [62]

Answer:

3x3x1

9x1x1

9x.5x2

3 0
4 years ago
la un joc pe calculator, trei copii au castigat inpreuna 780 de puncte. Al doilea copil a castigat de 3 ori mai multe puncte dec
ratelena [41]

Answer:

The number of points won by the first child was 37 points

The number of points won by the second child was 119 points

The number of points won by the third child was 624 points

Step-by-step explanation:

<u><em>The question in English is</em></u>

In a computer game, three children won together 780 points. The second child gained 3 times more points than the first and 8 more points, the third child gained four times more points than the first two in one place. How many points did each child earn

Let

x ----> number of points won by the first child

y ----> number of points won by the second child

z ----> number of points won by the third child

we know that

three children won together 780 points

so

x+y+z=780 ----> equation A

The second child gained 3 times more points than the first and 8 more points

y=3x+8 ----> equation B

the third child gained four times more points than the first two in one place

z=4(x+y) ----> equation C

Solve the system by substitution

step 1

substitute equation B in equation C

z=4(x+3x+8)

z=16x+32 ----> equation D

step 2

substitute equation D and equation B in equation A

x+(3x+8)+(16x+32)=780

step 3

solve for x

20x+40=780\\20x=740\\x=37

step 4

Find the value of y

y=3(37)+8=119

step 5

Find the value of z

z=16(37)+32=624

therefore

The number of points won by the first child was 37 points

The number of points won by the second child was 119 points

The number of points won by the third child was 624 points

4 0
3 years ago
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