The equilibrium constant expression for this reaction that takes place in water and involve ions can be written as K= [H_3 O^+ ][OH^- ]/([H_2 O] ^2 ). But the concentration of undissociated water, H_2 O is much larger than the concentration of the ions that is essentially remains constant. Therefore, we can include it in the equilibrium constant. The resulting new equilibrium constant can be written: K_W= [H_3 O^+ ][OH^- ].
A mass of protons and neutrons. Hope this helps. Abby (I'm really awesome)
Answer:
4p
Explanation:
3s < 3p < 4s < 4p
This arrangement is in order of increasing energy.
This explains that, 4p is the highest energy level you can reach.
The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.
The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an
individual gas in a mixture and n is total moles of the gas mixture. We
know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in
total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate
the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole
fraction of gas Y (x) and the total pressure (P) to calculate the
partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =
2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =
1.6 atm.
Answer:
0.031 parts per million
Explanation:
80 micrograms/m^3 = 80 micrograms/m^3 × 1m^3/1000L = 0.08 micrograms/L
Concentration in parts per million = concentration in micrograms/L × molar volume/MW
Concentration in micrograms/L = 0.08
Molar volume at 25°C and 101.325kPa (1 atm) is 24.45L
MW of SO2 = 64g/mole
Concentration in ppm = 0.08×24.45/64 = 0.031 ppm
