Question

a gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressute of 2.1 atm. what is he partial pressure of gas Y?

Answer 1

The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.

The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an

individual gas in a mixture and n is total moles of the gas mixture. We

know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in

total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate

the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole

fraction of gas Y (x) and the total pressure (P) to calculate the

partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =

2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =

1.6 atm.

Answer 2

this would equal 1.6 atm