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Inessa05 [86]
3 years ago
11

What is the maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol? Why?

Computers and Technology
2 answers:
KATRIN_1 [288]3 years ago
6 0

Answer:

Under IEEE 802.1Q, the maximum number of VLANs on a given Ethernet network is 4,094 (4,096 values provided by the 12-bit VID field minus reserved values at each end of the range, 0 and 4,095).

Explanation: found it from google

BartSMP [9]3 years ago
3 0

Answer:

4096 VLANs

Explanation:

A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.

An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²).  This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs

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The brute strength method determines if each x and y value satisfies both conditions. To do this, we must iterate through each result in the specified range and insert them into both models.

<h3>What are Elegant mathematical technique?</h3>

ALGORITHM :

1. Take the values of all coefficients and SET flag = FALSE

2. Run a FOR loop for x in range (-10, 11). 11 won't be included.

2a. Inside the first FOR, start the y FOR loop in range(-10,11). 11 won't be included

2b. Inside the y FOR loop, check IF for a particular value of x and y both the equations satisfied.

2c. If yes, set flag TRUE and print values of x and y.

2d. ELSE the flag stays FALSE.

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3. Check if flag = FALSE, then print NO SOLUTION

PYTHON CODE :

a=int(input()) #taking input for each coefficient

b=int(input())

c= int(input())

a1= int(input())

b1= int(input())

c1= int(input())

flag = False

for x in range(-10,11): #checking for all values of x in range -10 to 10

for y in range(-10,11): #checking for all values of x in range -10 to 10

if (a  x + b  y – c == 0) and (a1*x + b1*y - c1 == 0) : #checking if the x and y values satisfy the equation

flag = True #setting the flag if solution is found

print('Solution : x = {-10, 10}, y = {-10, 10}'.format(x,y)) #if they satisfy print x & y

if flag = False : #if flag stays false, that means there is no solution

print('No solution')

OUTPUT : The output is given below.

More about the Elegant mathematical technique link is given below.

brainly.com/question/27934739

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Answer:

def occurencesOfWords(words,freq):

  frequency_dictionary={}

  matched_frequency_words=[]

  for i in range(len(words)):

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      a=words[i].lower()

      for j in range(len(words)):

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              continue

          b=words[j].lower()

          if(a==b):

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      frequency_dictionary[words[i]]=counter

  for key in frequency_dictionary:

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if __name__=='__main__':

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  required_words=occurencesOfWords(words,freq)

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  • Inside the occurencesOfWords function, initialize a frequency_dictionary that is used to store the string and the frequency of that specific string .
  • matched_frequency_words is an array that is used to store each string whose frequency matches with the provided frequency
  • Run a nested for loop up to the length of words and inside the nested for loop, skip the iteration if both variables i and j are equal as both strings are at same index.
  • Increment the counter variable, if two string are equal.
  • Loop through the frequency_dictionary to get the matching frequency strings .
  • Finally test the program inside the main function.
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