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Stels [109]
3 years ago
15

Plzzz help i need this today :(

Computers and Technology
1 answer:
Juliette [100K]3 years ago
8 0

Answer:

C

Explanation:

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write a C program the prints out the size of variables with the following C data types- int, long, unsigned, long long, double,
Anit [1.1K]

<u>C program for finding size of different data types</u>

#include <stdio.h>

//driver function

int main()

{

   int a;  //declaring a of type int

   float b; //declaring b of type float

   double c; //declaring c of type double

   char d; //declaring d of type char

   long e; //declaring e of type long

   long long f; //declaring f of type longlong

   unsigned g; //declaring g of type unsigned

   // Sizeof operator is used to evaluate the size of a variable

printf(" int data type contains: %lu bytes\n",sizeof(a));/*Finding size of int */

printf("float data type contains : %lu bytes\n",sizeof(b));/*Finding size of float */

printf("double data type contains: %lu bytes\n",sizeof(c));/*Finding size of double */

printf("char data type contains: %lu byte\n",sizeof(d));/*Finding size of char */

printf("long data type contains: %lu byte\n",sizeof(e));/*Finding size of long*/ printf("longlong data type contains: %lu byte\n",sizeof(f));/*Finding size of longlong */

printf("unsigned data type contains: %lu byte\n",sizeof(g)); /*Finding size of unsigned */

   return 0;

}

<u>Output</u>

int data type contains: 4 bytes

float data type contains : 4 bytes

double data type contains: 8 bytes

char data type contains: 1 byte

long data type contains: 8 byte

longlong data type contains: 8 byte

unsigned data type contains: 4 byte

4 0
3 years ago
Please discuss what you consider to be some of the biggest challenges your company will face when working from the Linux command
Nastasia [14]

Answer:

Command remembering issues.

Explanation:

The biggest challenge my company will face when working on Linux is remembering issues of the commands. The commands in Linux are a bit difficult to remember as they are complicated bit but practice can solve this issue. "Practice makes a man perfect" this well known saying suggests that practice can make perfect and this well known saying also works with Linux the more practice the employees do the more perfect they get.

3 0
3 years ago
Write down the numbering system from base 2 to 200​
natka813 [3]

Answer:

So, 11001000 is the binary equivalent of decimal number 200 (Answer).

 

3 0
3 years ago
Higher resolution images mean they can be enlarged better, <br> True or false
ella [17]

Answer:

False

Explanation:

High resolution just mean It looks better

6 0
3 years ago
Read 2 more answers
Write a C++ programthat reads in the side of a square and prints out a pattern on$
AnnZ [28]

Answer:

#include<iostream>

using namespace std;

//main function

int main(){

   //initialize the variables

   int side;

   //print the message

   cout<<"Please enter the side of square: ";

   cin>>side;  //read the vale and store in the variable.

   // for loop

   for(int i=1;i<=side;i++){  //lop for rows

       for(int j=1;j<=side;j++){   //loop for column

           cout<<"$";  //print the '*'

       }

       cout<<endl;

   }

}

Explanation:

Create the main function and declare the variable side.

print the message on the screen for the user and then store value enter by the user on the variable side.

take the nested for loop for print the pattern.

nested for loop means, loop inside another loop it is used for print the pattern having rows and columns.

the first loop updates the row number and the second the loop print the character '$' in the column-wise.

in the code,

if i = 1, for loop check the condition 1 <= 5 if the value of side is assume 5.

condition is true and the program moves to the second for loop and starts to print the character '$' five times after that, print the new line.

then, the above process repeat for different rows and finally, we get the pattern in square shape.

7 0
3 years ago
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