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4 years ago

Solve the equation -3 = 8x - 4yfor y

Mathematics

1 answer:

Anestetic [448]4 years ago

8 0

You would add 4y to both sides of the equation which would leave you with

4y - 3 = 8x

then you would divide the entire equation by 4 leaving you with

y - 3/4 = 2x

then you would add 3/4 to both sides of the equation leaving you with

y = 2x + 3/4

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Phoenix [80]

Answer:

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3 years ago

Read 2 more answers

Check all of the correct solutions to this problem

MA_775_DIABLO [31]

To solve a quadratic equation $ax^2+bx+c=0$ we can use the quadratic formula:

$x_{1,2} = \cfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In your case, the equation is identified by $a=c=1,\ b=-5$

So, the solving formula yields

$x_{1,2} = \cfrac{5\pm\sqrt{25-4}}{2} = \cfrac{5\pm\sqrt{21}}{2}$

So, the two solutions are derived by choosing the plus sign once, and the minus sign the other time:

$x_{1} = \cfrac{5+\sqrt{21}}{2},\quad x_{2} = \cfrac{5-\sqrt{21}}{2}$

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3 years ago

Stephen places £950 in a bank account that pays 1.6% simple interest per year.

Gemiola [76]

A) 15.20
b) 965.2

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3 0

3 years ago

Find the height, x, of the tree.

Yuri [45]

Answer:

52.02 ft

Step-by-step explanation:

We can use equation tan θ = opposite/adjacent to solve for the opposite side x.

tan40° = x / 62

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4 0

4 years ago

The slope of the line below is -2. Write the point-slope equation of the line

kipiarov [429]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y-y_{0}=m(x-x_{0})$

Where:

m: It is the slope of the line

$(x_ {0}, y_ {0})$ : It is a point through which the line passes.

We have to:

$m = -2$

Thus, the equation is of the form:

$y-y_{0}=-2(x-x_{0})$

We substitute the point $(x_{0}, y_{0}) :( 4, -6)$

$y-(-6)=-2(x-4)\\y+6=-2(x-4)$

Finally, the equation is:

$y+6=-2(x-4)$

Answer:

$y = -2x + 2$

$y+6=-2(x-4)$

6 0

3 years ago