Answer:
Expand by multiplying x2+4x-4 by multiplying by x+4. Distribute and get x3+8x2+12x-16. You can verify it is correct by dividing by x+4 and you will arrive at x2+4x-4.
Given:
To find:
The number of possible solutions, if the Order of Operations did not exist.
Solution:
We have,
Now,
Case 1:
![[4 + 9 + 16] \div [4 - 8 -(3 \times 5)]=29\div (4 - 8 -15)](https://tex.z-dn.net/?f=%5B4%20%2B%209%20%2B%2016%5D%20%5Cdiv%20%5B4%20-%208%20-%283%20%5Ctimes%20%205%29%5D%3D29%5Cdiv%20%284%20-%208%20-15%29)
Case 2:
![[4 + 9 + 16] \div (4 - 8 -3) \times 5=29\div (-7\times 5)](https://tex.z-dn.net/?f=%5B4%20%2B%209%20%2B%2016%5D%20%5Cdiv%20%20%284%20-%208%20-3%29%20%5Ctimes%20%205%3D29%5Cdiv%20%20%28-7%5Ctimes%205%29)
Case 3:
Many more possibilities are there.
Therefore, there are more than 3 possible solutions.
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:
an = a1 + (n-1)d
where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.
First, we need to calculate for d from the given values above.
<span>a1 = 38 and a17 = -74
</span>
an = a1 + (n-1)d
-74 = 38 + (17-1)d
d = -7
The 27th term is calculated as follows:
a27 = a1 + (n-1)d
a27= 38 + (27-1)(-7)
a27 = -144 -----------> OPTION D
Answer:
-8 = m-2+b
-2 = m-0+b
4 = m2+b
10 = m4+b
Step-by-step explanation:
You just put them in y = mx+b format
