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Bess [88]
3 years ago
7

Identify the 27th term of an arithmetic sequence where a1 = 38 and a17 = -74. . A. -20.5 . B. -151 . C. -22.75 . D. -144 . .

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
7 0
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.  
<span>a1 = 38 and a17 = -74
</span>

an = a1 + (n-1)d
-74 = 38 + (17-1)d
d = -7

The 27th term is calculated as follows:

a27 = a1 + (n-1)d
a27= 38 + (27-1)(-7)
a27 = -144 -----------> OPTION D
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Answer:

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Step-by-step explanation:

We know the 2(length + width) = 34, and we know that length = 3+width. Therefore, we can use substitution. 2(3+width+width) = 34, and we can see that the width is 7. The length of the rectangle is 7+3=10

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3 years ago
jacque purchased 6 tickets to a hockey game. if the total cost was $225 what is the cost for one ticket
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37.5

Step-by-step explanation:

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Randall makes chilli for a cold winter night. To make 7 servings, he uses 12 1/4 cups of diced tomatoes. How many cups of diced
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Answer:

1.25 cups of diced tomatoes

Step-by-step explanation:

1.  12 1/4 ÷ 7

2. = 49/4 x 1/7

3.  =49/28

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6 0
2 years ago
Find the equation of a line with slope -6 that goes through the point (-2,23)
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6 0
3 years ago
Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma
Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with \mu = 112 inches and \sigma = 14 inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - \mu = 112 inches

Standard deviation - \sigma = 14 inches

The z-score formula is given by, Z=\frac{x-\mu}{\sigma}

Now,

P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})

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The Z-score value we get is from the Z-table,

P(X>140)=1-0.9772

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Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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3 years ago
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