Easy, it says "for ANY positive integer" so just test any positive integer
remember that n! means times all integers from 1 to that number n
lets try 1
(1+1)!/(1!)-1=
(2!)/(1!)-1=
2/1-1=
2-1=
1
if you don't believe me, try 2
(2+1)!/(2!)-2=
(3!)/(2!)-2=
(6)/(2)-2=
3-2=
1
te answer is 1, B
and number 9
easy, remember the exponential law
(x^m)(x^n)=x^(m+n)
jsut add the exponents
first gropu like bases
(r^2r^2/3)(t^1/2t^-3/2)
add bases
(r^2 and 2/3)(t^-1)=
(r^2∛(r^2))(1/t)=
![\frac{r^{2} \sqrt[3]{r^{2}} }{t}](https://tex.z-dn.net/?f=%20%5Cfrac%7Br%5E%7B2%7D%20%5Csqrt%5B3%5D%7Br%5E%7B2%7D%7D%20%7D%7Bt%7D%20)
In three-dimensional geometry, skew lines are two lines that do not intersect and are not parallel. A simple example of a pair of skew lines is the pair of lines through opposite edges of a regular tetrahedron. Two lines that both lie in the same plane must either cross each other or be parallel, so skew lines can exist only in three or more dimensions. Two lines are skew if and only if they are not coplanar. Hope this helps!! :)
how many pounds does he feed his dogs for each meal?
1/10 of .9 is the same as dividing .9 by 10.
.90 / 10 = .09
.09 is the answer
Answer:
Since he can't work a fraction of a day, he'll have to work at least 6 days to have enough money for the tank. The inequality hat represents his situation is 23*x + 20 >=140.
Step-by-step explanation:
In order to create an inequality to this problem we first need to take the initial amount he has and sum it with the days he has to work "x" multiplied by the amount he earns each day. We then have:
saleem money = 20 + 23*x
Since he wants to buy a $140 fish tank he needs to work until his money is greater or equal than this amount. So we have:
23*x + 20 >= 140
23*x >= 140 -20
23*x >= 120
x >= 120/23
x >= 5.22
Since he can't work a fraction of a day, he'll have to work at least 6 days to have enough money for the tank. The inequality hat represents his situation is 23*x + 20 >=140.
