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3 years ago

What is the slope of a line that passes through points (8,4) and (5,3)

Mathematics

1 answer:

expeople1 [14]3 years ago

7 0

Answer:

1/3

Step-by-step explanation:

We can find the slope of a line by using

m = (y2-y1)/(x2-x1)

= (3-4)/(5-8)

= -1/-3

=1/3

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35-40 first with the correct answers will get brainliest

serious [3.7K]

Answer:

35.w/g=m

36. P=1/2Q-15

37. R=IV

38. b=-mx+y

39. a) t=-d-e+f

b) t=19.175

40. No, X=-2.4

Step-by-step explanation:

Explanation for 40:

2(x-4)-4x=-6x+9x+4

first do the parentheses

2x-8-4x=-6x+9x+4

next combine like terms

-2x-8=3x+4

add 2x to each side

-8=5x+4

subtract 4 from each side

-12=5x

divide both sides by 5

x=-2.4

7 0

3 years ago

Which statement is true about the radical expression square root of 25

Lena [83]

Answer:

Step-by-step explanation:

The square Root of 25 in its simplest form means to get the number 25 inside the radical √ as low as possible.

25 is a perfect square, which means that you can simply calculate the square Root of 25 to get the answer. 5 times 5 equals 25. Thus, the square Root of 25 in simplest radical form is = 5

3 0

3 years ago

Find the area of the rectangle with the given base and height.

Temka [501]

Answer: 3 1/3 ft^2

Step-by-step explanation:

Start by converting the inches into feet

1 ft = 12 in

4 in/1 x 1 ft/ 12 in = 4/12 ft = 1/3 ft

Now, imagine just multiply like normal for a rectangle:

Area of a rectangle = base x height

Area of rectangle = (10 ft) (1/3 ft)

Area of rectangle = 3 1/3 ft^2

5 0

3 years ago

What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that ap

Bond [772]

So the right options are:

$y=-\frac{2}{5}x-1$

$2x+5y = -5$

$y-1=-\frac{2}{5}(x+5)$

Further explanation:

Given equation of line is:

2x+5y=10

We have to convert it into point-slope form

$2x+5y=10\\5y=-2x+10\\Dividing\ both\ sides\ by\ 5\\y=-\frac{2}{5}x+\frac{10}{5}\\y=-\frac{2}{5}x+2$

The co-efficient of x is the slope of the line

So,

$m= -\frac{2}{5}$

As the required line is parallel to given line, it will also have same slope.

Let m1 be the slope of required line

Then the line will be:

$y=m_1x+b$

Putting the value of slope

$y=\frac{2}{5}x+b$

Putting (-5,1) in the equation to find the value of b

$1=-\frac{2}{5}(-5)+b\\1=2+b\\b=1-2\\b=-1$

Putting the values of slope and b in equation

$y=-\frac{2}{5}x-1$

Multiplying the whole equation by 5 will give us:

5y = -2x-5

2x+5y = -5

Another form of equation of line is Point-slope form

$y-y_1=m(x-x_1)$

Putting the values of slope and point in the equation, we get

$y-1=-\frac{2}{5}(x+5)$

So the right options are:

$y=-\frac{2}{5}x-1$

$2x+5y = -5$

$y-1=-\frac{2}{5}(x+5)$

Keywords: Point-Slope form, Parallel lines

Learn more about point slope form at:

#LearnwithBrainly

4 0

3 years ago

Read 2 more answers

PLS HELP!!!

stira [4]

Answer: Option 4

Step-by-step explanation:

$\mathbf{u}=\langle 70 \cos 230^{\circ}, 70 \sin 230^{\circ} \rangle\\\\\mathbf{v}=\langle 60\cos 140^{\circ}, 60 \sin 140^{\circ} \rangle\\\\\mathbf{w}=\langle 80 \cos 30^{\circ}, 80 \sin 30^{\circ} \rangle\\\\\\\therefore \mathbf{u}+\mathbf{v}+\mathbf{w}=\langle 70 \cos 230^{\circ}+60 \cos 140^{\circ}+80 \cos 30^{\circ}, 70 \sin 230^{\circ}+60 \sin 140^{\circ}+80 \sin 30^{\circ} \rangle\\\\ \approx \langle -21.675, 24.944 \rangle$

$\implies |\mathbf{u}+\mathbf{v}+\mathbf{w}| \approx \sqrt{(-21.675)^2 + (24.944)^2} \approx 33.046$

Direction: The vector is in the second quadrant, so the direction is about $180^{\circ}-\arctan \left(\frac{24.944}{-21.675} \right) \approx 131^{\circ}$

8 0

1 year ago