Answer:
1/2187 is the 10th answer in the sequence
Step-by-step explanation:
just keep dividing the number by 3
1/9, 1/27, 1/81, 1/243, 1/729, 1/2187
Answer: Area (upper bound) = 4527.7056 cm²
Perimeter (lower bound) = 278 cm
<u>Step-by-step explanation:</u>
The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:
LENGTH: rounded to 87.3, actual is between 87.25 and 87.34
<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>
<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>
WIDTH: rounded to 51.8, actual is between 51.75 and 51.84
<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>
<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>
To find the Area of the upper bound, multiply the highest possible length and the highest possible width:
A = 87.34 × 51.84 = 4527.7056
To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:
P = 2(87.25 + 51.75) = 278
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
answer = -13
Step-by-step explanation:
number = x
x - 8 = -21
x = -21 + 8
= -13
Recheck :
num = - 13
decreased by 8 = - 13 -8 = -21
