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jasenka [17]
3 years ago
13

*math please help brainliest*

Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

\dfrac{3x+4}{2x-2}

Step-by-step explanation:

Invert and multiply the way you would any fraction division problem. Then cancel common factors from numerator and denominator.

\displaystyle\frac{\left(\frac{4x^2+2x}{x^2+x-2}\right)}{\left(\frac{8x^2+4x}{3x^2+10x+8}\right)}=\frac{4x^2+2x}{x^2+x-2}\cdot\frac{3x^2+10x+8}{8x^2+4x}\\\\=\frac{2x(2x+1)(3x+4)(x+2)}{4x(2x+1)(x-1)(x+2)}=\frac{3x+4}{2(x-1)}\\\\=\frac{3x+4}{2x-2}

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