math please help brainliest

Mathematics

1 answer:

valentinak56 [21]3 years ago

4 0

Answer:

$\dfrac{3x+4}{2x-2}$

Step-by-step explanation:

Invert and multiply the way you would any fraction division problem. Then cancel common factors from numerator and denominator.

$\displaystyle\frac{\left(\frac{4x^2+2x}{x^2+x-2}\right)}{\left(\frac{8x^2+4x}{3x^2+10x+8}\right)}=\frac{4x^2+2x}{x^2+x-2}\cdot\frac{3x^2+10x+8}{8x^2+4x}\\\\=\frac{2x(2x+1)(3x+4)(x+2)}{4x(2x+1)(x-1)(x+2)}=\frac{3x+4}{2(x-1)}\\\\=\frac{3x+4}{2x-2}$

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