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3 years ago

Consider the division problem 1/2÷ 3. Describe a situation this division could represent.

Mathematics

2 answers:

Alekssandra [29.7K]3 years ago

6 0

You could have half a cookie, divide it into thirds. (a semi circle cut into thirds)

vovikov84 [41]3 years ago

4 0

Half of a pizza divided into 3 pieces

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Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco

kari74 [83]

Answer:

C. $\frac{1}{18}$

Step-by-step explanation:

Given: Six cards numbered from $1$ to $6$ are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is $8$ , what is the probability that one of the two cards drawn is numbered $5$ .

Solution:

Sample space for sum of cards when two cards are drawn at random is $\{(1,1),(1,2),(1,3)......(6,6)\}$

total number of possible cases $=36$

Sample space when sum of cards is $8$ is $\{(3,5),(5,3),(6,2),(2,6),(4,4)\}$

Total number of possible cases $=5$

Sample space when one of the cards is $5$ is $\{(5,3),(3,5)\}$

Total number of possible cases $=2$

Let A be the event that sum of cards is $8$

$p(\text{A})$ $=\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}$

$p(\text{A})=\frac{5}{36}$

Let B be the event when one of the two cards is $5$

probability than one of two cards is $5$ when sum of cards is $8$

$p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}$

$p(\frac{\text{B}}{\text{A}})=\frac{2}{5}$

Now,

probability that sum of cards $8$ is and one of cards is $5$

$p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})$

$p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}$

$p(\text{A and B})=\frac{1}{18}$

if sum of cards is $8$ then probability that one of the cards is $8$ is $\frac{1}{18}$ , option C is correct.

3 0

3 years ago

Find a third-degree polynomial equation with rational coefficients that has roots -4 and 6 + i.

dolphi86 [110]

Answer:

x³ - 8x² - 11x + 148

Step-by-step explanation:

Given that x = 6 + i is a root then x = 6 - i is also a root

Complex roots occur as conjugate pairs.

The factors are therefore (x - (6 + i)) and(x - (6 - i))

Given x = - 4 is a root then (x + 4) is a factor

The polynomial is the product of the factors, that is

p(x) = (x + 4)(x - (6 + i))(x - (6 - i))

= (x + 4)(x - 6 - i)(x - 6 + i)

= (x + 4)((x - 6)² - i²)

= (x + 4)(x² - 12x + 36 + 1)

= (x + 4)(x² - 12x + 37) ← distribute

= x³ + 4x² - 12x² - 48x + 37x + 148

= x³ - 8x² - 11x + 148

3 0

3 years ago

Lucas wants to prove that the base angles of any isosceles triangle are

Dmitrij [34]

Answer:

EG so that GF ≈ EF

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A=lw+wh+lh, solve for w

KIM [24]

Subtract what is to the right of the equal sign form both side of the equation but any way the answer is 0

6 0

2 years ago

Read 2 more answers

32) (a)-(c) pre calculus

Harrizon [31]

Well, remember we can't take the square root of a negative

so we see that we have $\sqrt{1-x^2}$
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain

b. for a TI-84, go to y-editor then input $4x \sqrt{1-x^2}$ for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7

A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7

8 0

3 years ago