An outdoor deck is 7 feet wide. The perimeter of the Deck is 64 feet. what is the length of the deck?

Find the range of the function y=7x-1 when the domain is {-1, 0, 1}

mrs_skeptik [129]

Answer:

b

Step-by-step explanation:

6 0

2 years ago

Tamia watched 1 2 of a movie in the morning, and she watched some more at night. By the end of the day, she still had 1 3 of the

KonstantinChe [14]

Answer: Tamiya watched $\dfrac16$ of the movie at night.

Step-by-step explanation:

Let x = part of movie watched at night.

Given : Tanya watched $\dfrac12$ of movie in the morning.

Part left to watch = $\dfrac13$

As per given, we have

$\dfrac12+x+\dfrac13=1\\\\\Rightarrow\ x=1-\dfrac13-\dfrac12\\\\\Rightarrow\ x=\dfrac{6-2-3}{6}\\\\\Rightarrow\ x=\dfrac16$

Hence, Tamiya watched $\dfrac16$ of the movie at night.

8 0

2 years ago

Snog can you answer this question what is (3x4)-4(3-6)+14(7x8)

aliina [53]

Answer: 808

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The diagram represents the relationship of number sets. The four choices given will complete the diagram. Which BEST describes

NISA [10]

It’s D.
Natural numbers are 1,2,3,4,5,etc...
Whole numbers are 0,1,2,3,4,5,etc...
Integers are -1,-2,-3,-4,-5,-6,etc...
Rational numbers are -8/12, 2/3, 0.468,etc...

5 0

2 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 437437 green peas and 129129 yellow peas. Use

navik [9.2K]

Answer:

The null hypothesis: $\mathbf{H_o: p=0.27}$

The alternative hypothesis: $\mathbf{H_1: p \neq 0.27}$

Test statistics : z = −2.30

P-value: = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and conclude that under the same circumstances the proportion of offspring peas will be yellow is not equal to 0.27

Step-by-step explanation:

From the given information:

Let's state the null and the alternative hypothesis;

Since The claim is that 27% of the offspring peas will be yellow.

The null hypothesis state that the proportion of offspring peas will be yellow is equal to 0.27.

i.e

$\mathbf{H_o: p=0.27}$

The alternative hypothesis state that the proportion of offspring peas will be yellow is not equal to 0.27

$\mathbf{H_1: p \neq 0.27}$

<u>The test statistics:</u>

we are given 437 green peas and 129 yellow apples;

Hence;

$\hat p = \dfrac{x}{n}$

where ;

$\hat p$ = sample proportion

x = number of success

n = total number of the sample size

$\hat p = \dfrac{129}{437+129}$

$\hat p = \dfrac{129}{566}$

$\mathbf{\hat p = 0.2279}$

Now; the test statistics can be computed as :

$z = \dfrac { \hat p -p }{\sqrt {\dfrac{p(1-p)}{n} } }$

$z = \dfrac {0.2279 -0.27 }{\sqrt {\dfrac{0.27(1-0.27)}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {\dfrac{0.27(0.73)}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {\dfrac{0.1971}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {3.48233216*10^{-4} } }$

$z = \dfrac {-0.043 }{0.01866} }$

z = −2.30

C. P-value

P-value = P(Z < z)

P-value = P(Z< -2.30)

By using the P-value method and the normal distribution as an approximation to the binomial distribution.

from the table of standard normal distribution

move left until the first column is reached. Note the value as –2.0

move upward until the top row is reached. Note the value as 0.30

find the probability value as 0.010724 by the intersection of the row and column values gives the area to the left of

z = -2.30

P- value = 2P(z ≤ -2.30)

P-value = 2 × 0.01072

P - value = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and conclude that under the same circumstances the proportion of offspring peas will be yellow is not equal to 0.27

8 0

3 years ago