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2 years ago

20=x/3-8 what is x please help

Mathematics

1 answer:

malfutka [58]2 years ago

6 0

20=x/3-8

28=3x

3x/3 = 28/3

X= 28/3

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Given 16 = −5 + z4solve for z

AysviL [449]

Hi,

$16 = - 5 + z4 \\ - 4z + 16 = - 5 \\ - 4z = - 5 - 16 \\ - 4z = -21$

Now just divide both sides of equation by -4.

$z = \frac{21}{4}$

Simplify:

$z = 5 \frac{1}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: fraction \: result$

Decimal form:

$z = 5.25 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: decimal \: result$

Hope this helps.
r3t40

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3 years ago

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Yul has lunch at a resterant if his bill was $14.50 and yul wants to leave a 20% tip what is the amount he should leave for the

Triss [41]

14.50 times 0.20 = 2.9

He would give a $2.90 as a tip of 20% from a bill of $14.50

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3 years ago

HELP ME!!!PLEASE ITS DUE TODAY!!

Radda [10]

Answer:

25quarts of grape juice, 50 quarts of water

Step-by-step explanation:

Do the math

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3 years ago

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I don't understand how you find the value of expressions. Ex.. 5•[7+7÷(6+1)]+4•12

Alexxandr [17]

= [7+7 ÷ 7] + 4.12
= [7+1] + 4.12
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2 years ago

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At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes

lakkis [162]

Answer:

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

Step(i):-

Mean of the Population = 1900

Given random sample size 'n' = 45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

Null Hypothesis:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

Alternative Hypothesis :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step(ii):-

Test statistic

$t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }$

t = -900 /33.54 = -26.517

|t| = |-26.517|=26.517

Degrees of freedom

γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

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2 years ago