3 years ago

A student expanded an expression, as shown. Is the student's work correct? Explain why or why not.

2 answers:

7 0

No, the work is not correct. The distributive property was not used properly to expand the expression. Negative 6 should be multiplied by both terms in the parentheses. The second product should be -6 times -2/13 to get positive 12/13.

alex41 [277]3 years ago

4 0

The work is incorrect.

(-6) multiplies both terms inside parentheses. For some reason, the student changed the sign of that multiplier for the second term. The second term of the result should have a positive sign, the result of multiplying (-6)(-2/13) = +12/13.

You might be interested in

Evaluate the integral ∫_0^1{36dx/((2x+1)^3)}

german

$36 \int\limits^1_0 { \frac{1}{(2 x + 1) ^{3} } } \, dx =$
u = 2 x + 1, d u = 2 d x, d x = d u / 2
$36*1/2 \int\limits^1_0 {u ^{-3} } \, du = 18 * t ^{-2}/(-2) = \\ - 9 * t^{-2}= \\ -9 * ( 2 x + 1 ) ^{-2}$
- 9 / ( 2 + 1 )² - ( - 9 / ( 0 + 1 )² =
- 9 / 9 + 9 = - 1 + 9 = 8

3 0

3 years ago

4 5/9 + 2 5/6 + 1 2/3 ANSWER ASAPPPPP

lubasha [3.4K]

Answer:

9.05

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The high temperature one day was 30 Fahrenheit. Then the temperature dropped 23 degrees during the night. Does the expression 30

erastovalidia [21]