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Tomtit [17]
2 years ago
6

A semicircle and a quarter circle are attached to the sides of a rectangle as shown.

Mathematics
2 answers:
kobusy [5.1K]2 years ago
5 0
109 I hope I helped!! have a great day
IceJOKER [234]2 years ago
4 0

Answer:

If this is the shape, then it would be 109 :)

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If there was a graphical representation, I would be happy to assist you.

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The water under a draw bridge was 15 feet deep at midnight. As the tide went out, the
Vsevolod [243]

Answer:

80 minutes or 1 h 20 minutes

Step-by-step explanation:

15-13=2

2/0.025=80

So we can conclude that it takes 80 minutes till it reaches 13 feet.

7 0
3 years ago
A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
(A) Write an expression that represents Sarah’s total pay last week. Represent her hourly wage with (w)?
garri49 [273]

Answer:

Step-by-step explanation:

7 0
2 years ago
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