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lozanna [386]
3 years ago
7

A fish tank has 240 quarts of water. Levi adds another 120 quarts to the tank.

Mathematics
2 answers:
Tema [17]3 years ago
7 0

Answer:

90

Step-by-step explanation:

240+120=360

360/4=90

4=quarts per gallon

Sphinxa [80]3 years ago
6 0

Answer:

90 gallons

Step-by-step explanation:

1 gallon is 4 quarts. First find the total quarts which is 360, then divide by 4 to find the number of gallons which is 360/4 = 90 gallons

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A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be desc
g100num [7]

Answer:

y - Q = -5/2(x - P)

Step-by-step explanation:

The equation of a line in point slope form is expressed as y - y0 = m(x-x0)

(x0, y0) is the point

m is the slope

Given the equation

y = 2/5x− 4.

Slope m  = 2/5

Slope of the perpendicular line = -1/(2/5) = -5/2

Point;

x0 = P

y0 = Q

Substitute into the formula;

y - y0 = m(x-x0)

y - Q = -5/2(x - P)

This gives the required equation

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2 years ago
Evaluate the expression. 33 + 35 - 8 x (16 ÷ 4)
Mila [183]

Answer:

−32x+68

Step-by-step explanation:

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7 0
2 years ago
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A salesperson earns 7.5% commission on each vehicle sold. What price
Eddi Din [679]
Hey there! I’m just going to write out how I would solve this.

3,000=7.5%⋅x
100/7.5=13 1/3
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5 0
2 years ago
What are the vertices of A'B'C if ABC is dilated by a scale factor of 2?
malfutka [58]

The vertices of A'B'C' if A(0, 10), B(8, 6), C(4, 2) is dilated by a scale factor of 2 are;

  • C. A'(0, 20), B'(16, 12), C'(8, 4)

<h3>Which method can be used to find the vertices of A'B'C'?</h3>

Given that triangle ABC is dilated by a scale factor of 2, we have;

A'B' = 2 × AB

A'C' = 2 × AC

B'C' = 2 × BC

Length of AB = √((8-0)^2 + (6-10)^2) = 4•√5

Length of AC = √((4-0)^2 + (2-10)^2) = 4•√5

Length of BC = √((8-4)^2 + (6-2)^2) = 4•√2

By multiplying the given coordinates by the scale factor, we have;

A' = 2 × (0, 10) = (0, 20)

B' = 2 × (8, 6) = (16, 12)

C' = 2 × (4, 2) = (8, 4)

A'B' = √((16-0)^2 + (12-20)^2) = 8•√5

A'C' = √((8-0)^2 + (4-20)^2) = 8•√5

B'C' = √((16-8)^2 + (12-4)^2) = 8•√2

Therefore when we have;

A'(0, 20), B'(16, 12), C'(8, 4), we get;

  • A'B' = 2 × AB
  1. A'C' = 2 × AC
  2. B'C' = 2 × BC

The correct option is therefore;

  • C. A'(0, 20), B'(16, 12), C'(8, 4)

Learn more about finding the distance between points on the coordinate plane here:

brainly.com/question/7243416

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5 0
1 year ago
Can someone help me pleaseee...​
grandymaker [24]

Answer:

what you need help with?

Step-by-step explanation:

3 0
3 years ago
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