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julia-pushkina [17]
3 years ago
7

Is square root of 100 irrational or rational?

Mathematics
2 answers:
viva [34]3 years ago
7 0
<span>Square root of 100 is a rational number. Because sqaure rooot 100 = 10. And, 10 can be written in the form rational number. Any number that can be written in the form of p/q where p and q are integers and q in not zero is called a rational number.</span>
Dennis_Churaev [7]3 years ago
5 0
For this case we have the following number:
 \sqrt{100}
 By power properties we can rewrite the number.
 We have then:
 \sqrt{100} =  \sqrt{10*10}
 \sqrt{100} =  \sqrt{10^2}
 \sqrt{100} = 10
 We observe that the result can be written as the quotient between two whole numbers.
 For example:
 \frac{200}{20} = 10
 This means that the number is rational.
 Answer:
 
square root of 100 is rational.
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Answer:

Option D.

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Step-by-step explanation:

The coordinates of a point in space must necessarily have 3 components. One to describe the distance on the x axis, another to describe the distance on the y axis to the point, and a third to describe the distance on the z axis.

If we have three variables, then 3 equations are needed to solve the system. With less than 3 equations it would be impossible to solver the system.

Therefore the correct answer is option D.

3 equations with 3 variables

8 0
3 years ago
What is the next number 486, 162, 54, 18
Lesechka [4]
The pattern is to divide by 3

486 ÷ 3 = 162
162 ÷ 3 = 54
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  18 ÷ 3 = 6

The next number is 6
5 0
3 years ago
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Simplify using the multiplication rule.
goldenfox [79]

A. the first one is the answer

Step-by-step explanation:

3 0
3 years ago
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What is the inverse of 2(x+4)^2+8
Sedaia [141]
Find the inverse, interchange the variables to solve for y
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3 0
3 years ago
At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
4 0
3 years ago
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