The largest number of different whole numbers that can be on Zoltan's list is 999
<h3>How to determine the largest number?</h3>
The condition is given as:
Number = 1/3 of another number
Or
Number = 3 times another number
This means that the list consists of multiples of 3
The largest multiple of 3 less than 1000 is 999
Hence, the largest number of different whole numbers that can be on Zoltan's list is 999
Read more about whole numbers at:
brainly.com/question/19161857
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<u>9</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>solution</u><u>.</u>
Answer:
Solution given:
2x+10=28
subtracting both side by 10
2x+10-10=28-10
2x=18
dividing both side by 2
2x/2=18/2
x=9
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Answer:
No
Step-by-step explanation:
if im wrong forgive me if im right please mark brainleast
1+2=21, 2+3=36, 3+4=43, 4+5=52.
