Answer:
Determining flammability can be as simple as holding a sample of the substance over a match. If it burns, it is flammable, leading to additional experiments to find more properties. Measuring the heat given off by the substance when it burns gives the heat of combustion.
Explanation:
The wavelength of a photon that has an energy of E = 3.69×10−19 J is 5.42 x 10⁻⁷ m.
<h3>What do you mean by wavelength?</h3>
The space between corresponding points (adjacent crests) in adjacent cycles is known as the wavelength () of a waveform signal that is sent in space or down a wire.
The wavelength can be calculated by the given formula
E = hc/λ
Where, E is energy = 3.65 x 10⁻¹⁹ J
h is plank's constant = 6.626 x 10⁻³⁴ J.sec
c is speed of light = 2.9 × 10⁸ m/s
Putting the values in the formula
λ = (6.626 x 10⁻³⁴)(2.9 × 10⁸) / (3.65 x 10⁻¹⁹) = 5.42 x 10⁻⁷ m.
Thus, the wavelength, λ is 5.42 x 10⁻⁷ m.
Learn more about wavelength
brainly.com/question/13533093
#SPJ1
The pressure increases as temperature increases, as a gas is heated it expands, so in a confined container (constant volume) pressure must increase, this can be observed through the universal gas law (pv=nRT)
Answer:
C1V1=C2V2
C1 is 2.0mol/l
V1=?
C2=.4mol/L
V2=100ml or for this 0.1L
V1 is 20ml
Best way to prepare this is to measure out 20ml of the 2 molar solution and add 80mL to it to get to 100mL
Explanation:
Answer:
true
because with the both states we increase the surface of reaction
