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vivado [14]
3 years ago
14

80 liters of oxygen is collected over water at 50.0 degrees Celsius. The atmospheric pressure during the collection was 96.00 kp

a. What is the partial pressure of the oxygen?
Chemistry
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

The value of partial pressure of oxygen P_{O_{2} } = 83.66 K pa

Explanation:

Volume of oxygen = 80 liters

Temperature = 50°c

The total pressure = 96 K pa

The partial pressure of water at 50°c is calculated from the tables.

P_{H_{2}O } = 12.344 K pa

The total pressure is given by

P_{total} = P_{H_{2}O } + P_{O_{2} }

Put all the values in the above equation we get

96 = 12.344 + P_{O_{2} }

P_{O_{2} } = 96 - 12.344

P_{O_{2} } = 83.66 K pa

This is the value of partial pressure of oxygen.

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1) The heat of combustion for the gases hydrogen, methane and ethane are −285.8, −890.4 and −1559.9 kJ/mol respectively at 298K.
Morgarella [4.7K]

Answer:

The enthalpy of the reaction is 64.9 kJ/mol.

Explanation:

H_2 + \frac{1}{2}O_2\rightarrow H_2O,\Delta H_1 =-285.8 kJ..[1]

CH_4 + 2O_2\rightarrow CO_2 + 2H_2O,\Delta H_2 =-890.4 kJ..[2]

C_2H_6 + \frac{7}{2}O_2\rightarrow 2CO_2 + 3H_2O,\Delta H_3= -1559.9 kJ..[3]

2CH_4(g)\rightarrow C_2H_6(g) + H_2(g),\Delta H_4=?..[4]

2 × [2] - [1]- [3] = [4]  (Using Hess's law)

\Delta H_4=2\times \Delta H_2 -\Delta H_1 -\Delta H_3

\Delta H_4=2\times (-890.4 kJ)-(-285.8 kJ) -(-1559.9 kJ)

\Delta H_4=64.9 kJ/mol

The enthalpy of the reaction is 64.9 kJ/mol.

3 0
3 years ago
Calculate the density of CO2 at a pressure of 685.0 torr and 41.0°C . <br> R=0.0821 (L*atm)/(mol *K)
Keith_Richards [23]

T=41+273=314 k

M=(12)+(16×2)=44g/mol

d=PM/RT

d=685×44/0.0821×314

d=1169.15 g/L

5 0
2 years ago
1
zzz [600]

Answer:

i think kinetic energy sorry if I'm wrong.

6 0
3 years ago
What is the reactant(s) in the chemical equation below?
butalik [34]

Answer:

C. 3CO(g) + Fe2O3(s)

Explanation:

The substance(s) to the hath left of the arrow in a chemical equation art hath called reactants.  A reactant is a substance yond is presenteth at the starteth of a chemical reaction.  The substance(s) to the right of the arrow art hath called products.  A product is a substance yond is presenteth at the endeth of a chemical reaction

So in this example, 3CO(g) + Fe2O3(s) art the reactants.

The 2Fe(S) + 3CO2(G) art the products.

Desire I holp! Has't a most wondrous day!

Hope I helped!  Have a great day!

7 0
2 years ago
The heat of vaporization of water at 100°c is 40.66 kj/mol. Calculate the quantity of heat that is absorbed/released when 9.00 g
timofeeve [1]

Answer:

20.3 kJ of heat is absorbed when 9.00 g of steam condenses to liquid water.

Explanation:

Heat is being consumed during vaporization and heat is being released during condensation.

To vaporize 1 mol of water, 40.66 kJ of heat is being consumed.

Molar mass of water = 18.02 g/mol

Hence, to vaporize 18.02 g of water , 40.66 kJ of heat is being consumed.

So, to vaporize 9.00 g of water, (\frac{40.66}{18.02}\times 9.00)kJ of heat or 20.3 kJ of heat is being consumed

As condensation is a reverse process of vaporization therefore 20.3 kJ of heat is absorbed when 9.00 g of steam condenses to liquid water.

5 0
3 years ago
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