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vivado [14]
3 years ago
14

80 liters of oxygen is collected over water at 50.0 degrees Celsius. The atmospheric pressure during the collection was 96.00 kp

a. What is the partial pressure of the oxygen?
Chemistry
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

The value of partial pressure of oxygen P_{O_{2} } = 83.66 K pa

Explanation:

Volume of oxygen = 80 liters

Temperature = 50°c

The total pressure = 96 K pa

The partial pressure of water at 50°c is calculated from the tables.

P_{H_{2}O } = 12.344 K pa

The total pressure is given by

P_{total} = P_{H_{2}O } + P_{O_{2} }

Put all the values in the above equation we get

96 = 12.344 + P_{O_{2} }

P_{O_{2} } = 96 - 12.344

P_{O_{2} } = 83.66 K pa

This is the value of partial pressure of oxygen.

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<h3>Answer:</h3>

28 mol CaF

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.7 × 10²⁵ molecules CaF

[Solve] moles CaF

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                          \displaystyle 1.7 \cdot 10^{25} \ molecules \ CaF(\frac{1 \ mol \ CaF}{6.022 \cdot 10^{23} \ molecules \ CaF})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 28.2298 \ moles \ CaF

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

28.2298 mol CaF ≈ 28 mol CaF

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3 years ago
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