Answer:
2.83 g
Explanation:
At constant temperature and pressure, Using Avogadro's law
Given ,
V₁ = 2.12 L
V₂ = 3.12 L
n₁ = 0.120 moles
n₂ = ?
Using above equation as:
n₂ = 0.17660 moles
Molar mass of methane gas = 16.05 g/mol
So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g
<u>2.83 g are in the piston.</u>
The answer would be , True
Orbitals are space around the nucleus where electrons orbit. Several orbitals can exist in a given energy level/shell. Carbon is the sixth element of the periodic table with 6 electrons. Carbon atoms have the ability to bond to themselves and to other atoms with sp, sp² and sp³, hybrid orbitals. Several orbitals in carbon are spherical conformation and this accounts to about 40% of the orbitals.
Answer:
–1647.45 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 112.5 g
Initial temperature (T₁) = 12.5 °C
Final temperature (T₂) = 9°C
Specific heat capacity (C) = 4.184 J/g°C
Heat (Q) absorbed =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial temperature (T₁) = 12.5 °C
Final temperature (T₂) = 9°C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 9 – 12.5
ΔT = –3.5 °C
Finally, we shall determine the heat absorbed. This can be obtained as follow:
Mass (M) = 112.5 g
Change in temperature (ΔT) = –3.5 °C
Specific heat capacity (C) = 4.184 J/g°C
Heat (Q) absorbed =?
Q = MCΔT
Q = 112.5 × 4.184 × –3.5
Q = –1647.45 J
Answer:
Dipole moment of H₂O: 2.26 Debye
Bond angle in H₂S: 89.7°
Explanation:
The total dipole moment(μr) for H₂O can be calculated by the sum of the dipole moments of each bond of O-H. Because the dipole moment is a vector, the sum of these vectors can be calculated by the cosine law.
μr² = (μO-H)² + (μO-H)² + 2*(μO-H)*(μO-H)*cos(104.5°)
μr² = 1.85² + 1.85² + 2*1.85*1.85*cos(104.5°)
μr² = 3.4225 + 3.4225 + 6.845*(-0.2504)
μr² = 5.13115
μr = √5.13115
μr = 2.26 Debye.
For H₂S:
0.95² = 0.67² + 0.67² + 2*0.67*0.67*cosθ
0.9025 = 0.4489 + 0.4489 + 0.8978cosθ
0.8978cosθ = 0.0047
cosθ = 0.00523
θ = arcos0.00523
θ = 89.7°
