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Lunna [17]
3 years ago
11

A pound of margarine costs $1.39. What is the cost of a kilogram of margarine

Chemistry
1 answer:
den301095 [7]3 years ago
8 0

Answer:

              3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

                                    1 Kilogram  = 2.20462 Pounds

Hence, as given,

                        1 Pound of Margarine costs  =  1.39 Dollars

So,

                  2.20462 Pounds Margarine will cost  =  X Dollars

Solving for X,

                     X  =  (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

                     X =  3.064 Dollars

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Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

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Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

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