complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
<span>
<span>
</span>
2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
</span><span>
<span>
</span>
3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
</span><span>
<span>
</span>
4. complete the squre and expand
</span>
so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
3 is 23 degree
8 is 157 degree
Answer:
-1/2 and -1
Step-by-step explanation:
This is the answer I used in my test, not sure if it is correct, but hope it helps!
Answer:
23+5y=23x +5
5y=23x-18
y=23/5x - 18/5
<u>y--7=</u>23/5
x-6
5y+35=23x-138
5y=23x-203
y=23/5x -203/5
Step-by-step explanation:
Answer:
Yes because 20 percent of anything, including 0, multiplied by 5 is 100 percent
Step-by-step explanation:
