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photoshop1234 [79]
3 years ago
6

12. Elly's credit card record for the last 7 months is below. Based on the information from the table, what will be her new bala

nce at the end of month 77
End of
Month
New
Charges
S2200.00
$0.00
Previous
Balance
$0.00
$2200.00
52189.00
S2178.06
S2167.16
S2156.33
S2145.55
$0.00
50.00
$0.00
$0.00
50.00
Payment
Received
50.00
$44.00
S43.78
$1356
$43.36
S43.13
54291
Finance
Charges
50.00
$33.00
$32.84
$32.67
$32.51
S32 34
532.18
Principal
Peid
30.00
$11.00
$10.95
$10.89
$10.84
$10.78
$10.73
New
Balance
52200.00
S2189.00
$2170.06
$2157.16
52156.33
52145 55
Mathematics
2 answers:
Tema [17]3 years ago
6 0

Answer:

2134.82

Step-by-step explanation:

blagie [28]3 years ago
4 0

Answer:

52145.55

Step-by-step explanation:

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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
3 years ago
Mike withdrew $32 from his bank account. The transaction slip said his balance was $289.14. What was his previous balance?
Temka [501]
<span>His previous balance was $321.14
289.14 + 32 = 321.14

hope this helps
</span>
4 0
3 years ago
Find the missing angles in the following triangles.
Bezzdna [24]

Answer:

Step-by-step explanation:

angles in triangle = 180

1. 180 - (70+45) = x = 65

2. x = 35

180 - 110 = 70

70/2 = 35 (isosceles triangle)

3. x = 113, y = 67

180 - (62 + 51) = y = 67

Angles on a line = 180

180 - 67 = x = 113

4. x = 60, y = 50

x = 180 - 120 = 60

y = 180 - (60 + 70) = 50

answers in degrees.

8 0
3 years ago
A ball is shot straight up into the air from the ground with initial velocity of 45ft/sec. Assuming that the air resistance can
Nesterboy [21]
V2^2 = V1^2 - 2gh 

<span>=> 0 = 44^2 - 2 (32.2) h </span>

<span>=> h = 44^2 / 64.4 = 30.062 ft</span>
6 0
3 years ago
If mAGF = mBGC = mDGC = mEGF = 67°, what is mAGB?
lesantik [10]
Ggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg
4 0
4 years ago
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