Answer:
0 ≤y ≤ 60
Step-by-step explanation:
The range is values the y can take
y goes from 0 to 60
10 ≤y ≤ 60
Let W = width of package
Let H = height of package
Let L = length of package
The perimeter cab be one of the following:
P = 2(L + W), or
P = 2(L + H)
The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
2(L + 10) <= 108
L + 10 <= 54
L <= 44 in
When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in
To satisfy both of these conditions requires that L <= 39 in.
Answer: 39 inches
Answer:
134 children and 120 adult plates were served
Step-by-step explanation:
let the children mean be x
Let the adult meal be y
If fourteen less children’s meals were served than adult meals at a barbecue, then;
y = x - 14 .... 1
IF Children plate were 1.50 each and adult plates were 2.00 each with a total of 441 in amount then;
1.5x + 2y = 441 .... 2
Substitute 1 into 2;
1.5x + 2(x-14) = 441
1.5x+2x-28 = 441
3.5x = 441+28
3.5x = 469
x = 469/3.5
x = 134
Recall that y = x - 14
y = 134-14
y = 120
Hence 134 children and 120 adult plates were served
Answer:
Option D
Step-by-step explanation:
Given that a producer ships boxes of produce to individual customers.(say x)
X is a normal random variable with mean = 36 and std dev =4 lbs
By definition of std normal variate we know that
is N(0,1)
75th percentile of std normal distribution is
0.675
Hence corresponding x would be
Option D matches with this value
Hence answer is option D
Answer:
141
Step-by-step explanation:
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