Answer:
16
Step-by-step explanation:
Answer: C
Step-by-step explanation:
Okay first set a comparison since the two triangles are similar
x-1/20=x-1+27/3x+8
x-1/20 = x+26/3x+8
cross multiply
20x+520=3x^2+8x-3x-8
3x^2-15x-528=0
3(x^2-5x-176)=0
im kinda lazy to factor this out so i used an online calculator right here but factor it out like a good kid
x=16, x=-11
it has to be positive so x=16
C
We'll check if they're orthogonal:
u*v=0
(6,-2)*(8,24)=0
6*8+(-2)*24=0
48-48=0
0=0
they are orthogonal vectors
Answer:
=6x+3y
Step-by-step explanation:
3X+3(X+Y)
Distribute:
=3X+(3)(X)+(3)(Y)
=3X+3X+3Y
Combine Like Terms:
=3x+3x+3y
=(3x+3x)+(3y)
=6x+3y
Given the function f(x)=x^2+5x+5 , to get the zeros we solve using quadratic formula;
x=[-b(+or-) sqrt(b^2-4ac)]/(2a)
from our function;
a=1,b=5, c=5
thus,
x=[-5(+or-)sqrt(5^2-4*1*5)]/(2*1)
x=[-5(+or-)sqrt(25-20)]/2
x=[-5+/-sqrt(5)/2
The answer is option C
