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frutty [35]
3 years ago
6

Ashley and joe each improved their yards by planting hostas and ornamental grass. They bought their supplies from the same store

. Ashley spent $152 on 12 hostas and 8 bunches of ornamental grass. Joe spent $66 on 6 hostas and 3 bunches of ornamental grass. Find the cost of one hosta and the cost of one bunch of ornamental grass.
Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

one hosta=$6

one ornamental grass=$10

Step-by-step explanation:

6 10?

6*6+3*10

36+30

66

12*6+8*10

72+80=152

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A person borrowef Rs 16000 from a bank at 12.5% pet annum simple intrest and lent the whole amount to shopkeeper at the sam rate
r-ruslan [8.4K]

Answer:

The amount he gains in 2 years is Rs. 250

Step-by-step explanation:

The parameters of the amount borrowed from the bank are;

The amount borrowed, P = Rs. 16,000

The interest rate of the amount borrowed, R = 12.5%

The number of years, T = 2 years

The simple interest, I = (P × R × T)/100 =  (Rs. 16,000 × 12.5 × 2)/100 = Rs. 4,000

The total amount the person is to pay bank to the bank = P + I = Rs. 16,000 + Rs. 4,000 = Rs. 20,000

The parameters of the amount lent to the shopkeeper are;

The amount lent, P = Rs. 16,000

The compound interest rate of the amount lent, R = 12.5%

The number of years, T = 2 years

The amount he receives from the shopkeeper after 2 years, A = P·(1 + R/n)^(n × T) = Rs. 16,000 × (1 + 0.125/1)^(1 × 2) = Rs. 20,250

The amount he gains in 2 years = The amount he receives from the shop keeper - The amount he gives to the bank = Rs. 20,250 - Rs. 20,000 = Rs. 250

The amount he gains in 2 years = Rs. 250.

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2 years ago
Find the side in of point a to point c
vladimir1956 [14]

Step 1:

Calculate the measure of angle ∠ABC

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From the triangle in the question,

a=10\operatorname{km},c=15\operatorname{km},B=115^0

Step 2:

Calculate the value of AB using the cosine rule below

b^2=a^2+c^2-2\times a\times c\times\cos B

By substituting the values, we will have

\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}

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The distance of point A to point C is = 21.26km

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