What is 4 x312 but in distributive property

In AKLM, m = 1.2 cm, k = 5.1 cm and

Elodia [21]

Answer:

4.2 cm

Step-by-step explanation:

The law of cosines is applicable.

l² = k² +m² -2km·cos(L)

l² = 5.1² +1.2² -2·5.1·1.2·cos(35°) ≈ 17.4236

l ≈ √17.4236

l ≈ 4.2 . . . cm

4 0

3 years ago

A tattoo enthusiast website claims that :

KATRIN_1 [288]

Answer:

The probability that a person is a Millennial given that they have tattoos is 0.5069 (50.69%) or about 0.51 (51%).

Step-by-step explanation:

We have here a case where we need to use Bayes' Theorem and all conditional probabilities related. Roughly speaking, a conditional probability is a kind of probability where an event determines the occurrence of another event. Mathematically:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

In the case of the Bayes' Theorem, we have also a conditional probability where one event is the sum of different probabilities.

We have a series of different probabilities that we have to distinguish one from the others:

The probability that a person has a tattoo assuming that is a Millennial is:

$\\ P(T|M) = 0.47$

The probability that a person has a tattoo assuming that is of Generation X is:

$\\ P(T|X) = 0.36$

The probability that a person has a tattoo assuming that is of Boomers is:

$\\ P(T|B) = 0.13$

The probability of being of Millennials is:

$\\ P(M) = 0.22$

The probability of being of Generation X is:

$\\ P(X) = 0.20$

The probability of being of Boomers is:

$\\ P(B) = 0.22$

Therefore, the probability of the event of having a tattoo P(T) is:

$\\ P(T) = P(T|M)*P(M) + P(T|X)*P(X) + P(T|B)*P(B)$

$\\ P(T) = 0.47*0.22 + 0.36*0.20 + 0.13*0.22$

$\\ P(T) = 0.204$

For non-independent events that happen at the same time, we can say that the probability of occurring simultaneously is:

$\\ P(M \cap T) = P(M|T)*P(T)$

Or

$\\ P(T \cap M) = P(T|M)*P(M)$

But

$\\ P(M \cap T) = P(T \cap M)$

Then

$\\ P(M|T)*P(T) = P(T|M)*P(M)$

We are asked for the probability that a person is a Millennial given or assuming that they have tattoos or P(M | T). Solving the previous formula for the latter:

$\\ P(M|T)*P(T) = P(T|M)*P(M)$

$\\ P(M|T) = \frac{P(T|M)*P(M)}{P(T)}$

We have already know that

$\\ P(T|M) = 0.47\;P(M) = 0.22\;and\;P(T) = 0.204$ .

Therefore

$\\ P(M|T) = \frac{0.47*0.22}{0.204}$

$\\ P(M|T) = 0.50686 \approx 0.51$

Thus, the probability that a person is a Millennial given that they have tattoos is 0.5069 (50.69%) or about 0.51 (51%).

5 0

3 years ago

Write the first five terms of the geometric sequence in which a1=8 and the common ratio is -1/2.

Oliga [24]

Answer:

First five terms are:

8 , (-4) , 2 , (-1) , (1/2)

Step-by-step explanation:

$a_{1}=8 \\\\r = \frac{-1}{2}\\\\a_{2}=\frac{-1}{2}*a_{1}= \frac{-1}{2}*8= -4\\\\a_{3}=\frac{-1}{2}*a_{2}=\frac{-1}{2}*-4=2\\\\a_{4}=\frac{-1}{2}*a_{3}=\frac{-1}{2}*2=-1\\\\a_{5}=\frac{-1}{2}*a_{4}=\frac{-1}{2}*-1=\frac{1}{2}$

4 0

3 years ago

A single die is rolled twice. Find the probability of rolling an

Nady [450]

Answer: 1/6

Step-by-step explanation:

A die has 6 numbers which are 1, 2, 3, 4, 5 and 6.

Odd numbers in a die = 1, 3 and 6

Numbers greater than 4 = 5 and 6

Probability of rolling an odd number = 3/6 = 1/2

Probability of rolling a number greater than 4 = 2/6 = 1/3

We then multiply both values gotten. This will be:

= 1/2 × 1/3

= 1/6

Therefore, the probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6.

6 0

3 years ago

PLEASE HELP I RLY NEED THIS! I BEG YALL PLEASE HELP ME !

GalinKa [24]

Answer:

The answer would be 30/13.

Step-by-step explanation:

Votes for the skating rink= 30

Votes for the bowling alley= 13

Ratio of the # of votes for skating <u>TO</u> the # of votes for the bowling alley= 30/13.

Hope this helps! :)

8 0

3 years ago