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2 years ago

What is the measure of m_A?

Mathematics

1 answer:

Leto [7]2 years ago

8 0

Answer:

m∠A=52°

Step-by-step explanation:

Because of the exterior angle theorem, m∠A+m∠B=105° (The exterior angle)

We then end up with an equation like this...

m∠A+m∠B=105°

Then, you do the substitution...

x+53°=105°

Subtract 53 from both sides...

x=105°-53°

x=52°

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if a lake has high alkalinity, what is closest to the probability that the lake also has a shallow depth?

never [62]

Answer:

0.22

Step-by-step explanation:

Probability distribution is the function which describes the likelihood of possible values assuming a random variable. The alkalinity of lake is determined by dividing the high shallow depthness by the total of lake alkalinity. The shallow depth is 209 and the total alkalinity of the lake is 966. By dividing the depthness with alkalinity we get 0.22.

209/966 = 0.219

approximately 0.22

8 0

3 years ago

Help me please will mark brainlyist

Leni [432]

Answer:

24.46

Step-by-step explanation:

4 0

3 years ago

A ball is thrown into the air from an apartment balcony and falls to the ground. The height of the ball, h metres, t seconds aft

andriy [413]

Answer:

$1+2\sqrt{2}$ seconds

Step-by-step explanation:

When the ball hits the ground, its height will obviously be 0. Therefore, you can set up the equation the following way:

$0=-5t^2+10t+35 \\\\-5(t^2-2t-7)=0$

Plugging this into the quadratic equation, you get:

$t=\dfrac{2\pm\sqrt{4+28}}{2}= \\\\\dfrac{2\pm4\sqrt{2}}{2}= \\\\1\pm2\sqrt{2}$

Since the time must be positive, it takes the ball $1+2\sqrt{2}$ seconds to hit the ground, or around 3.828. Hope this helps!

7 0

2 years ago

Please help me with this problem!): (#5)

astra-53 [7]

5a.

18/9 = 12/x

18x = 12(9)...cross multiply

18x = 108

x=108/18

x=6

6 0

2 years ago

At the center of espionage in Kznatropsk one is thinking of a new method for sending Morse telegrams. Instead of using the tradi

alexgriva [62]

Answer:

It takes less time sending 5 letters the traditional way with a probability of 36.7%.

Step-by-step explanation:

First we must take into account that:

- The traditional method is distributed X ~ Poisson(L = 1)

- The new method is distributed X ~ Poisson(L = 5)

$P(X=x)=\frac{L^{x}e^{-L}}{x!}$

Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events (to send 5 letters) in a unit of time for both methods, so:

- For the traditional method:

$P(X=5)=\frac{1^{5}e^{-1}}{1!}\\\\P(X=5) = 0.367$

- For the new method:

$P(X=5)=\frac{5^{5}e^{-5}}{5!}\\\\P(X=5) = 0.175$

According to this calculations we have a higher probability of sending 5 letters with the traditional method in a unit of time, that is 36.7%. Whereas sending 5 letters with the new method is less probable in a unit of time. In other words, we have more events per unit of time with the traditional method.

7 0

2 years ago