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2 years ago

ASAP!! PLS HELP! thx!!!!!

Mathematics

1 answer:

mr Goodwill [35]2 years ago

6 0

Answer:

Step-by-step explanation:

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In CAT entrance examination paper there are 3 sections, each containing 5 questions. A candidate has to solve 5,

mamaluj [8]

The best and most correct answer providedfrom your question about the entrance examination paper is the second option which is 2,250. The problem can be solved by:

3-1-1 : 5c3*5c1*5c1 *3!/2! = 750
<span>2-2-1 : 5c2*5c2*5c1 *3!/2! = 1500
</span>
Adding the two answers:

750 + 1500 = 2250

I hope it has come to your help.

4 0

3 years ago

I need help with this problem y=5x-3

defon

Answer:

Slope= 5

y intercept= (0,-3)

Step-by-step explanation:

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2 years ago

2 + 3x²y - 1⁄2y + y - 1

Svet_ta [14]

Answer:

3x²y+0.5y+1

Step-by-step explanation:

2+3x²y -0.5y+y -1

2 and -1 is 1

-0.5y and +y is +0.5y so the answer is...

4 0

2 years ago

Find the value of x.

svetoff [14.1K]

Answer:

Step-by-step explanation:

1) Find the interior angle using relations of angles in straight line I.e ( sum of angles in a straight line is 180 ) and we know the sum of all the interior angle of quadrilateral is 360 degree .

2) Solve further for x.

5 0

2 years ago

Find sin 2a and cot 2a:

geniusboy [140]

Answer:

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}$

Step-by-step explanation:

$\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\$

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}$

8 0

3 years ago