Answer:
Solution given:
f(x)=x²
g(x)=x+5
h(x)=4x-6
now
23:
(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25
24:
(gof)(x)=g(f(x))=g(x²)=x²+5
25:
(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36
26:
(hof)(x)=h(f(x))=h(x²)=4x²-6
27;
(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1
28:
(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14
Answer:
6 groups
2 girls, 3 boys
Step-by-step explanation:
To find the answer, first find the Greatest Common Factor or the GCF. The GCF in this case is 6. So, the amount of groups is 6. Then divide each number by 6, so there will be 2 girls in each group and 3 boys in each group.
Answer:
3
Step-by-step explanation:
Integers: 0, 1, 2, 3, 4
0 + 1 + 2 + 3 + 4 = 10
The probability is 0.0008.
I used a binomial probability on this one, since there are two outcomes (either pass or fail); the events are independent (the probability of one person passing does not influence the probability of another passing); and there are a fixed number of trials (in this case, 20).
For binomial probabilities, we use the formula:

With our information, we have: