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Sloan [31]
3 years ago
9

Find the x- and y- intercepts of the equation -x+5y=10.

Mathematics
1 answer:
mario62 [17]3 years ago
4 0

Answer:

X Intercept: (-10,0), Y Intercept: (0,2)

Step-by-step explanation:

Well, firstly you need to rewrite the equation to make it easier. After rewriting it you have the equation y=x/5+2 by adding the x to the right side and dividing everything by 5. Now simply plug in your zeroes in their respective places. For the x intercept, your y value must equal 0 so we have the equation 0=x/5+2. After solving it, x must be -10 in order for our y value to be 0 getting us for the x intercept (-10,0). For the y intercept, your x value must equal zero so you simply subsitute zero in the equation for x which I will do here: y=0/5+2. If our x value is zero, consequently, our y value will be 2 getting us for the y intercept, (0,2).

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Please help me:(*********​
Licemer1 [7]

Answer:

x = 16

Step-by-step explanation:

I could be wrong so sorry in advance lol but this is what I did:

I made the equation 3x + 3 = ((7x-10)/2)

I divided the 2nd equation by 2 so that it would be the same length as RZ.

after that, I got: 3x + 3 = 3.5x - 5

from there, i did basic algebra to get the answer 16

hope this helps!

6 0
3 years ago
1) The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 5 years. Using the
8090 [49]

Answer:

1) 68%

2) 68%

Step-by-step explanation:

<h2>1) The ages of trees</h2>

We know the mean and the standard deviation.

The mean is:

\mu=25

The standard deviation is:

\sigma=5

The Z-score formula is:

Z = \frac{x-\mu}{\sigma}

For x=20 the Z-score is:

Z_{20}=\frac{20-25}{5}=-1

For x=30 the Z-score is:

Z_{30}=\frac{30-25}{5}=1

Then we look for the percentage of the data that is between -1 deviations from the mean.

According to the empirical rule 68% of the data is less than 1 standard deviations of the mean.  This means that 68% of the trees are between 20 and 30 years old

<h2>2) Pizza delivery </h2>

First we calculate the Z-scores

We know the mean and the standard deviation.

The mean is:

\mu=27

The standard deviation is:

\sigma=3

The z-score formula is:

Z = \frac{x-\mu}{\sigma}

For x=24 the Z-score is:

Z_{24}=\frac{24-27}{3}=-1

For x=30 the Z-score is:

Z_{30}=\frac{30-27}{3}=1

Then we look for the percentage of the data that is between -1 deviations from the mean.

According to the empirical rule 68% of the data is less than 1 standard deviations of the mean.  This means that 68% of pizzas are delivered between 24 and 30 minutes

8 0
3 years ago
An education researcher collects data on how many hours students study at various local colleges. The researcher calculates an a
fgiga [73]

Answer:

Correct option is (B) descriptive statistical method

Step-by-step explanation:

Descriptive statistics branch in statistics deals with the representation of the data using distinct brief coefficients. These coefficients are used as either the representative of the sample or the population.

The descriptive statistics branch is divided into two sub branches:

  1. Measure of central tendency
  2. Measure of dispersion.

The three measures of central tendency are:

  • Mean (or Average)
  • Median
  • Mode.

The measures of dispersion are:

  • Variance
  • Standard deviation
  • Range
  • Kurtosis
  • Skewness

The education researcher computes the average number of hours student study at various local colleges.

The average of a data is the mean value which is the measure of central tendency.

Thus, the researcher is using descriptive statistical method to summarize the data.

3 0
3 years ago
Who knows how to resolve this
Colt1911 [192]
You have to distribute the radical negative 18 in first. Simplifying from there, you’ll prob have to get into imaginary numbers since the square root of a negative is imaginary
8 0
3 years ago
Great Society programs of the 1960s led to
Setler [38]
Great Society programs of the 1960s led to <span>a decrease in the poverty rate. The correct option among all the options that are given in the question is the second option. The programs were launched by the american President, Lyndon B. Johnson. I hope the answer has come to your help.</span>
3 0
3 years ago
Read 2 more answers
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