3 years ago

How to solve these problems ?

Mathematics

2 answers:

garik1379 [7]3 years ago

8 0

You subtract the power from each other for example number 4 a^2 -a^1 = 2-1 = a^1

Sholpan [36]3 years ago

3 0

I can’t see the problems clearly

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Let $S = 2010 + 2011 + \cdots + 4018$. Compute the residue of $S$, modulo 2009.

Yakvenalex [24]

Notice that

2010 ≡ 1 mod 2009

2011 ≡ 2 mod 2009

2012 ≡ 3 mod 2009

...

4017 ≡ 2008 mod 2009

4018 ≡ 0 mod 2009

So really, S is just the sum of the first 2008 positive integers:

$S=\displaystyle\sum_{n=1}^{2008}n=\frac{2008\cdot2009}2$

where we invoke the formula

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

and so S ≡ 0 mod 2009.

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3 years ago

I need this answer asap

muminat

The answer would be -2/5...
just forget about the denominator, they all match up, just make the numerators equal 0

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Simora [160]

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mariarad [96]

Answer: 4

Step-by-step explanation:

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5 students have vanilla ice cream and 13 students have chocolate ice cream. What is the ratio of the number of students who have

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Answer:

5/13

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