PLEASE HELP ME ASAP!!!<br> I WILL MARK BRAINLIEST!!

Chipper had 189 hits in 572 at bats calculate chippers batting average for season by dividing the number if hits by the number o

lord [1]

Answer:

0.330

Step-by-step explanation:

Divide the number of hits (189) by the number of bats (572)

189/572=0.330

8 0

3 years ago

Integrate the following:<br><img src="https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Cint%20%5C%3A%20%20%5Ctan%28x%29%20%20%20%5

Korvikt [17]

Answer:

$\huge \boxed{\red{ \boxed{ - \cos(x) + C}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

integration
PEMDAS

<h3>tips and formulas:</h3>

$\tan( \theta) = \dfrac{ \sin( \theta) }{ \cos( \theta) }$
$\sf \displaystyle \int \sin(x) \: dx = - \cos(x) + C$

<h3>let's solve:</h3>

$\sf \: rewrite \: \tan( \theta) \: as \: \dfrac{ \sin( \theta) }{ \cos( \theta) } : \\ = \displaystyle \int \: \frac{ \sin(x) }{ \cos(x) } \cos(x) \: dx \\ = \displaystyle \int \: \frac{ \sin(x) }{ \cancel{\cos(x) }} \: \cancel{ \cos(x)} \: dx \\ = \displaystyle \int \: \sin(x) \: dx$
$\sf \: use \: the \: formula : \\ \sf \displaystyle - \cos(x)$
$\sf add \: constant : \\ - \cos(x) + C$

$\text{And we are done!}$

6 0

2 years ago

Read 2 more answers

What value of x is in the solution set of 3(x – 4) ≥ 5x + 2? <br><br> –10<br> –5<br> 5<br> 10

emmasim [6.3K]

<u>Answer:</u>

The value of x is in the solution set of 3(x – 4) ≥ 5x + 2 is -10

<u>Solution:</u>

Need to determine which value of x from given option is solution set of 3(x – 4) ≥ 5x + 2

Lets first solve 3(x – 4) ≥ 5x + 2

3(x – 4) ≥ 5x + 2

=> 3x – 12 ≥ 5x + 2

=> 3x – 5x ≥ 12 + 2

=> -2x ≥ 14

=> -x ≥ 7

=> x ≤ -7

All the values of x which are less than or equal to -7 is solution set of 3(x – 4) ≥ 5x + 2. From given option there is only one value that is -10 which is less than -7

Hence from given option -10 is solution set of 3(x – 4) ≥ 5x + 2.

7 0

3 years ago

Read 2 more answers

Which numbers are rational? select all that apply. A. pi B. √50 C. 2.3 D. √144

aev [14]

C. 2.3
D.√144

Rational roots or decimals are numbers that have an end point.

pi 'technically' never ends, while √50 = 7.07106781<span>…, which never ends either
</span>

hope this helps

5 0

3 years ago

Read 2 more answers

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

3 0

2 years ago

PLEASE HELP ME ASAP!!! I WILL MARK BRAINLIEST!!