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aliya0001 [1]
4 years ago
9

Which of the following inequalities define a region that contains all of Quadrant 3?

Mathematics
1 answer:
Bingel [31]4 years ago
3 0
Refer to the diagram shown below.

The shaded area satisfies the two inequalities
y > x - 1
and
y < 1 -x

Answer: A and D

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A counterexample for the expression sec(theta)/tan(theta)=sin(theta) is 45 degrees true of false
inessss [21]
A counterexample for the expression secФ / tanФ = sinФ is 45°
This is a FALSE statement.

Explanation:

Solving Right-hand side:

SecФ = 1 / CosФ

tanФ = SinФ / CosФ

secФ/tanФ = 1 / CosФ ÷ SinФ / CosФ

secФ/tanФ = 1 / CosФ × CosФ/SinФ

secФ/tanФ = CosФ / SinФCosФ

secФ/tanФ = 1 / SinФ

Hence,
            Left-hand side ≠ Right-hand side
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3 years ago
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Please help!
lisabon 2012 [21]

The leftmost line segment has a domain of -4 ≤ x < -1, or [-4, 1).

The central line segment has a domain of -1 ≤ x ≤ 2, or [-1, 2].

The rightmost line segment has a domain of 2 < x ≤ 5, or (2, 5].

Overall, this function has a domain of

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(where U means "union" in the set-theoretic notion)

But this also simplifies to the interval [-4, 5].

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Y = 3x<br> 5x + 2y = 44
faltersainse [42]

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Step-by-step explanation:

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