Which of the following inequalities define a region that contains all of Quadrant 3?
1 answer:
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Answer:
The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.
Step-by-step explanation:
Consider the system of linear equations:
The system of linear equations can have zero, one, or an infinite number of solutions:
simplify equation (1):
substitute in equation (2), we get
we cannot find the value of and
.
so, there is no solution.
Multiply the equation (1) with 3 and put k is 6,
it means both equations are overlapped. Then, the solution has infinite solutions.
Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.
Answer:
Option (C)
Step-by-step explanation:
There are two inequalities,
t - 4 ≥ 4t + 8 ------(1)
3t > 14 - 4t ------(2)
By simplifying inequality (1),
t - 4 ≥ 4t + 8
t ≥ 4t + 8 + 4
t ≥ 4t + 12
t - 4t ≥ 12
-3t ≥ 12
t ≤
t ≤ -4
By solving inequality (2),
3t > 14 - 4t
3t + 4t > 14
7t > 14
t >
t > 2
From the given graphs, Option (C) will be the answer.