Answer:
145
Step-by-step explanation:
Because what you want to do is add 260 to 182 then subtract from 587. I hope that helped! :)
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
739.47
Step-by-step explanation:
height - h, radius -r
V=hπ²r=5×3.14²×15=739.47
If you wash 4 cars you would get $20
Answer:

Step-by-step explanation:
Coordinate of B = 1
Coordinate of D = 6
Coordinate of A = -1
BD = |1 - 6| = 5 units
AD = |-1 - 6| = |-7| = 7 units

Plug in the values
