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2 years ago

Which of the following nonlinear inequalities is graphed below

Mathematics

1 answer:

Rashid [163]2 years ago

4 0

Answer:

(x²/4) + (y²/16) ≤ 1

Step-by-step explanation:

The general form of the ellipse in the graph is

x²/4 + y²/16 = 1

we want to find the inequality which represents the shaded area this will determine whether which of the following 2 choices are correct

Choice 1: x²/4 + y²/16 ≥ 1

Choice 2: x²/4 + y²/16 ≤ 1

we note that point (0,0) lies inside the shaded area. Which means if we substitute (0,0), it should create an equality that is valid.

try choice 1: 0²/4 + 0²/16 = 0 ≥ 1 (not valid because obviously zero is smaller than 1)

try choice 1: 0²/4 + 0²/16 = 0 ≤ 1 (this is valid, hence choice 2 is the answer)

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If the neighborhood holds 13 total games and all 50 athletes participate, how many 6-player games and how many 2-player games ar

nadezda [96]

Answer:

13 points

Step-by-step explanation:

Equation for "There are 50 athletes signed up for a neighborhood basketball competition. Players can select to play in the 6-player games ("3 on 3") or the 2-player games ("1 on 1").

Equation for "If the neighborhood holds 13 total games and all 50 athletes participate"

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8 0

2 years ago

Mia's credit card balance is less than -$85. Does she owe more or less than $85

dalvyx [7]

Mia's balance is at -85, which means she had $0,

and has spent $85.

This means that she needs to pay BACK $85, (+85)

and there might be an extra charge since she overspent on her account.

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3 years ago

Consider the following sets of matrices: M2(R) is the set of all 2 x 2 real matrices; GL2(R) is the subset of M2(R) with non-zer

defon

Answer:

Step-by-step explanation:

REcall the following definition of induced operation.

Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.

So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.

For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).

Case SL2(R):

Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So

$\text{det(AB)} = \text{det}(A)\text{det}(B)\neq 0$ .

So AB is also in SL2(R).

Case GL2(R):

Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So

$\text{det(AB)} = \text{det}(A)\text{det}(B)=1\cdot 1 = 1$ .

So AB is also in GL2(R).

With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).

7 0

2 years ago

At noon, a submarine was located at 5 12 meters below

Cerrena [4.2K]

-512 is the answer because 512 is a negative solution in Integers math

7 0

2 years ago

Answer please? ___ feet per second

Oksanka [162]

Answer: 30 feet per second

========================================

x = diameter, y = speed of water

y varies inversely with respect to x, so, y = k/x for some constant k

If x = 0.6 and y = 5 pair up, then y = k/x turns into 5 = k/0.6 which solves to k = 3 when you multiply both sides by 0.6

So the equation y = k/x turns into y = 3/x

Now plug in the diameter x = 0.1 to find the speed to be...

y = 3/x

y = 3/0.1

y = 30 feet per second

4 0

3 years ago