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Komok [63]
3 years ago
7

An airplane is flying at 35,000 feet above sea level airplane started to send a rate of 2500 ft./min. after five minutes how man

y feet above sea level is the airplane
Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Answer:

22,500 feet

Step-by-step explanation:

Initial Height of the airplane = 35000 feet

Rate of descend = 2500 ft/min

This means for every minute the height of the plane is decreasing by 2500 feet.

We have to find how high above the sea level is the airplane after 5 minutes.

Since, in one minute the distance of plane is decreasing by 2500 feet, in 5 minutes the decrease in its distance would be = 2500 x 5 = 12,500 feet

Thus, after 5 minutes the height of airplane would have decreased by 12,500 feet. Since, the initial height of airplane was 35,000 feet, the new height after 5 minutes would be:

Height after 5 minutes = 35000 - 125000 = 22,500 feet

After 5 minutes, airplane is 22,500 feet above the sea level

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An element with mass 490 grams decays by 28.6% per minute. How much of the element is remaining after 16 minutes, to the nearest
agasfer [191]

Answer:

2.2 grams

Step-by-step explanation:

We can use the compound decay formula shown below to solve this:

F=P(1-r)^t

Where

F is the final amount (what we want to find)

P is the present amount (490 grams)

r is the rate of decay, in decimal (28.6% = 28.6/100 = 0.286)

t is the time in minutes (16)

Substituting, we get:

F=P(1-r)^t\\F=490(1-0.286)^{16}\\F=490(0.714)^{16}\\F=2.2355

So, after 16 minutes, 2.2355 grams will be remaining.

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3 years ago
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ohaa [14]

Answer:

b=√119

Step-by-step explanation:

a2+b2=c2

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b=√119

5 0
3 years ago
1; 4; 16; 64; ...<br>what is the general term ​
Alborosie

Given:

The sequence is

1, 4, 16, 64

To find:

The general term of the given sequence.

Solution:

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1, 4, 16, 64

Here, the ratio between two consecutive terms is same. So, it is a geometric sequence.

First term is:

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Common ratio is:

r=\dfrac{a_2}{a_1}

r=\dfrac{4}{1}

r=4

The nth term of a geometric sequence is

a_n=ar^{n-1}             ...(i)

Where, a is the first term and r is the common ratio.

Putting a=1 and r=4 in (i), we get

a_n=(1)(4)^{n-1}

a_n=4^{n-1}

Therefore, the general term of the given sequence is a_n=4^{n-1}.

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igor_vitrenko [27]

Answer:

Step-by-step explanation:

2. Degree = 15

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3 years ago
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Butoxors [25]

Answer:

215

Step-by-step explanation:

60=50

258=?

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50 x 4.3 = 215

7 0
3 years ago
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