The Malthusian law for population growth have the folowing form:
the population of alligators in
where
is the initial population size , r is the rate of growth and t is time.
By substracting 1980 from t we could say that our
is 1700 (the population of alligators in 1980):

and that let us with:
Now we can solve for the 2005 population of 7000 alligator:

By knowing the definition of exponential we can solve:

now we can estimate by replacing t with 2020


So the approximate population in 2020 is 16364 alligators in that region.