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posledela
3 years ago
10

For what value of the variable the value of the expression 4(5x–8) is 4 more than the value of the expression 2(4–x)?

Mathematics
2 answers:
elixir [45]3 years ago
8 0

Answer:

For x=2

Step-by-step explanation:

This problem reduces to solving the equation

4(5x-8)=2(4-x)+4

we expand both sides

20x-32=8-2x+4

rearrange and solve for x:

22x=8+4+32

22x=44

\boxed{x=2}

which is our answer.

bearhunter [10]3 years ago
7 0

Answer:

what is the answer. can you give me an equation? That might help me be able to solve the problem. When I tried to do it, i got 18/11=x

Step-by-step explanation:

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En el pequeño frasco se colocaron 7 galletas para regalar si ornearon 56 ¿cuantos frascos. regalaron?​
Solnce55 [7]

Answer:

1 frasco

Step-by-step explanation:

En el pequeño frasco se colocaron 7 galletas para regalar si ornearon 56 ¿cuantos frascos. regalaron?

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Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC
e-lub [12.9K]

Answer:

DC=\frac{8}{3}\ units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

BM^2=AB^2-AM^2

we have

AB=5\ units\\AM=x\ units

substitute

BM^2=5^2-x^2

BM^2=25-x^2 -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

BM^2=BC^2-MC^2

we have

BC=7\ units\\MC=AC-AM=(9-x)\ units

substitute

BM^2=7^2-(9-x)^2

BM^2=49-(81-18x+x^2)  

BM^2=49-81+18x-x^2

BM^2=-x^2+18x-32 ----> equation B

equate equation A and equation B

-x^2+18x-32=25-x^2

solve for x

18x=25+32\\18x=57\\\\x=\frac{57}{18}

Simplify

x=\frac{19}{6}

<em>Find the length of DC</em>

DC=AC-2x

substitute the given values

DC=9-2(\frac{19}{6})

DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units

8 0
3 years ago
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kiruha [24]

Answer:

Provide a question pls :)

Step-by-step explanation:

Pls mark brainliest lol

6 0
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The sum of 3 numbers is 131. the second of three numbers is seven more than twice the first. the third number is 12 less than th
arsen [322]
A+b+c = 131

b = 7 + 2a and c = a - 12
 so a + 7+2a + a-12 = 131
then 4a -5 = 131
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6 0
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