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finlep [7]
3 years ago
9

-0.5(d - 1.5) = 2.5 What is d

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:A)0.5 We can see in the graph , that it is bell-shaped along x =2. A bell-shaped graph along one value is called symmetric graph and it represents a normal distribution.

Since, the give graph is symmetric around x=2, so the mean of the data is 2.

The point immediate left to the mean represents x-σ

so,

2 - σ = 1.5

So,

σ = 0.5

The sigma represents standard deviation.

Hence, Option A is correct ..

Step-by-step explanation:and what is on d is 2.5

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Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
Evaluate the expression if a = 9 and b = 2. 5(a 3b) 20 51 70 75
devlian [24]
5(a + 3b) = 5(9 + 3(2)) = 5(9 + 6) = 5(15) = 75
5 0
3 years ago
Y = 5x - 10 (solve for x)
worty [1.4K]

Answer:

(y+10)/5

Step-by-step explanation:

You start off by adding 10 on both sides cancelling the 10 on the right side and you get y+10=5x. From there you then divide by 5 on both sides and you get your answer of (y+10)/5.

4 0
3 years ago
A highly selective university will only admit students who place at least 2-zcores above the mean on the ACT that
Harrizon [31]

Answer:

30

Step-by-step explanation:

Each z-score = 1 standard deviation from the mean, so 18 + (6 x 2) = 30

3 0
2 years ago
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False, because it would no longer be 18 alone because of the disturbutive property.
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