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serious [3.7K]
3 years ago
12

We are interested in the dimensions of a certain rectangle. This rectangle has length triple the side of the square and width tw

o units less than the side of the square. If the two areas are equal, what are the rectangle's dimensions (w x h)?
Mathematics
1 answer:
sukhopar [10]3 years ago
4 0
Let s be the side of the square. The length of the rectangle is 3s and its width is equal to s - 2. From the given condition,
                              A (square) = A (rectangle)
                                 s² = (3s)(s - 2)
                                 s² = 3s² - 6s
                                   -2s² = -6s
                                       s = 3
Thus, the length of the rectangle is 9 and its width is 1
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Answer: A pair of boots costs $120.25. A pair of tennis shoes costs $75.87✔️

Step-by-step explanation:

Let B the cost of a pair of boots and let T the cost of a pair of tennis shoes.

Then we know:

A pair of boots and a pair of tennis shoes cost $196.12:

B + T = $196.12 } Equation 1

We also know:

The difference in their cost is $44.38:

B - T = $44.38 } Equation 2

From the equation 1 we know T:

T = $196.12 - B

Now we can substitute this value in equation 2:

B - ($196.12 - B) = $44.38

B - $196.12 + B = $44.38

2B = $44.38 + $196.12 = $240.5

B = $240.5/2 = $120.25◄cost of a pair of boots

Since we know the value of T from the equation 1:

T = $196.12 - B = $196.12 - $120.25 = $75.87◄cost of a pair of tennis shoes

Answer: A pair of boots costs $120.25. A pair of tennis shoes costs $75.87✔️

<h3>Verify </h3>

We can substitute these values in equations 1 and 2 and check the results:

B + T = $196.12 } Equation 1

$120.25 + $75.87 = 196.12 ✔️<em>check!</em>

B - T = $44.38 } Equation 2

$120.25 - $75.87 = $44.38 ✔️<em>check!</em>

Spymore

6 0
3 years ago
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Step-by-step explanation:

Given:

\sigma = 0.20\\\\c = 95\% = 0.95\\\\\therefore \alpha = 1- c = 1- 0.95 = 0.05\\\\\therefore  \frac{\alpha}{2} = 0.025\\\\

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E = 0.10\\\\n=(\frac{Z_{\frac{\alpha}{2} \times \sigma}}{E})^2

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so, The Sample size (n) = 16

For point b:

E = 0.06\\\\n=(\frac{Z_{\frac{\alpha}{2} \times \sigma}}{E})^2

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E = 0.04\\\\n=(\frac{Z_{\frac{\alpha}{2} \times \sigma}}{E})^2

    = (\frac{(1.96\times 0.20)}{0.04})^2\\\\=  96.04\approx  96

7 0
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