if an athlete’s weight decreased from 160 pounds to 152 pounds, what was the percent decrease in the athlete’s weight? a) 16% b)
10% c) 8% d) 5% e) 4%
1 answer:
Percent decrease=decrease/original
decrease=160-152=8
original=160
8/160=1/20=5/100=5%
5% decrease
D is answer
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Answer:
5,630.81$
A = 5000(1 + (0.04 × 3)) = 5600
A = $5,630.81
We can simplify this problem by pairing like terms together.
9x + 15x - 2x + 2
22x + 2
This expression can be simplified down to
22x + 2
Should be 65 degrees also
Hey there,
The answer is true
Hope it helped!
