The points are (-4,2) and (3,-4)
using y2-y1/x2-x1
-4-2/3-2
-6/1
slope (m) is -6
to find b part of equation (y=mx+b) plug in point value for x and y
2=-6(-4)+b (multiply -6 and -4)
2=24+b (subtract 24 over)
b=-22
final equation is y=-6x-22
Use the law of sines
11/sin50°=13/sinθ
11/0.766=13/sinθ
11sinθ=13(0.766)
11sinθ=9.958
sinθ=9.958/11
sinθ=0.9052727
use arcsin on your calculator
θ=64.86°
Answer:
14 and 6
Step-by-step explanation:
Let's start by naming the first number x.
We can name the second number y.
We can set up equations to model our situation.
x+y=2x-8
x-y=2y-4
Let's simplify the equations.
x+y=2x-8
Subtract 2x from both sides
-x+y=-8
__________
x-y=2y-4
Subtract 2y from both sides.
x-3y=-4
Add the two equations together to eliminate x.
x-3y=-4
-x+y=-8
________
0x-2y=-12
-2y=-12
Divide both sides by -2.
y=6
The second number is 6.
Plug that back in.
x+6=2x-8
Subtract x from both sides
6=x-8
Add 8 to both sides
x=14
The first number is 14
Step-by-step explanation:
y = mx + c, where m is the slope of the line and c is the y-intercept.
We have y = 3x - 4 as line L.
Slope of line L = 3
=> Slope of line L2 = -1/3
We have y = -1/3 x + c as our line L2 equation.
When x = 9, y = 5.
=> (5) = -1/3 * (9) + c
=> 5 = c - 3, c = 8
Hence the answer is y = -1/3 x + 8.
