Answer:
Using Matlab code for Fourier series to calculate for the function, see the attached
Step-by-step explanation:
Go through the picture step by step.
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
9514 1404 393
Answer:
(a) 75.5
Step-by-step explanation:
There are two ways you can work this.
<u>Pythagorean theorem</u>
Triangle CMP is a right triangle. CM = AC = 55. CP = CB -PB = 55 -15 = 40. Then length PM can be found from ...
PM² +CP² = CM²
PM = √(CM² -CP²) = √(55² -40²) = √1425 ≈ 37.749
The length MN is twice the length of PM, so is ...
MN = 2×PM = 2×37.349 = 75.498
The length of MN is about 75.5.
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<u>Using chord relationships</u>
The products of the different lengths for the same chord are the same for the crossed chords.
AP×PB = MP×PN
We know MP = PN, so ...
MP = √(AP×PB) = √((55+40)(15)) = √1425
As before, MN = 2×MP = 2√1425
MN ≈ 75.5
2 r π / 2 = 9.42 in
r π = 9.42 in
r = 9.42 : 3.14 = 3 in
Area of the circle:
A = r² π = 3² π = 9 π in² = 28.26 in²
