Sexual reproduction is an early
evolutionary modernization after the appearance of eukaryotic cells. During
sexual reproduction, the genetic material of two individuals is put together to
produce genetically-diverse offspring that is not the same from their parents. Actually
there are more eukaryotes reproduce sexually is the proof of its evolutionary
success. Most of the animals, it is actually the only way of reproduction. The
genetic diversity of sexually-produced offspring is thought to produced species
a better chance of surviving in a changing or unpredictable environment.
The variation that sexual
reproduction make among offspring is very important to reproduction of the
population and the survival .
In sexual reproduction, different
mutations are continually reshuffled from one generation to the next when
different parents combine their unique genomes; this results in an increase of
genetic diversity.
<span>On average, a sexually-reproducing population
will leave more offspring than an otherwise similar asexually-reproducing
population.</span>
<span>The answer is binary fission. This happens when during the replication of chromosomes of prokaryotes. Similar to mitosis, it divides itself and reproduces asexually. Many bacterias use this kind of process to produce more of this kind of organism inequal sizes. </span>
Answer:
28.57%
Explanation:
Given that:
= 10.0 mg/L
= 3.0 mg/L
We can calculate for the Original maximum deficit can be calculated which can be illustrated as follows:
where;
represents the maximum dissolved oxygen
represents the saturated dissolved oxygen
represents the minimum dissolved oxygen
= 10.0 mg/L - 3.0 mg/L
= 7.0 mg/L
We can also calculate the Desired maximum deficit by using the above expression:
In which ;
= 10.0 mg/L
= 5.0 mg/L
Now that we have all we need to replace the value; we have:
= 10.0 mg/L - 5.0 mg/L
= 5.0 mg/L
Finally, the percentage needed by the BOD for removing the waste can be determined using the following expression;
percentage = %
where;
Desired = 5.0 mg/L
Original = 7.0 mg/L
Then we have;
percentage = %
=71.43%
Required BOD = 100% - 71.43%
Required BOD = 28.57%
Hence, The percentage necessary for the BOD of the plant waste to be reduced to assure a healthy stream with at least 5.0 mg/L DO everywhere = 28.57%
<span>4
Nicotine is as harmful as smoking even much time. As the effects of Snuff are stronger and reactions faster in the blood than even for conventional cigarette smokers. The harmful side effects of smoking cigarette would be even more faster for snuff sniffers than cigarette smoker because of the level of nicotine</span>