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Fudgin [204]
3 years ago
14

Why do you think a removable discontinuity (hole) doesn't produce an asymptote on the graph of a polynomial function, even thoug

h it is excluded from the domain of the function?
Mathematics
1 answer:
Monica [59]3 years ago
8 0
Because  removable discontituity means that the limit of the function at that point has a finite value, and then you define the value of the function as that valu (the limit value).

An asymptote means that the limit of the function goes to positive or negative infinity.

You cannot meet both conditions, finite  and infinity limit at the same time.
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