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Svetach [21]
3 years ago
9

An object was launched off the top of a building. The function f(x)=-16x^2+16x+672 represents the height of the object above the

ground, in feet, x seconds after being launched. Find and interpret the given function values and determine an appropriate domain for the function.
Mathematics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

6x2 + 16x = 672

Reorder the terms:

16x + 16x2 = 672

Solving

16x + 16x2 = 672

Solving for variable 'x'.

Reorder the terms:

-672 + 16x + 16x2 = 672 + -672

Combine like terms: 672 + -672 = 0

-672 + 16x + 16x2 = 0

Factor out the Greatest Common Factor (GCF), '16'.

16(-42 + x + x2) = 0

Factor a trinomial.

16((-7 + -1x)(6 + -1x)) = 0

Ignore the factor 16.

Subproblem 1

Set the factor '(-7 + -1x)' equal to zero and attempt to solve:

Simplifying

-7 + -1x = 0

Solving

-7 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.

-7 + 7 + -1x = 0 + 7

Combine like terms: -7 + 7 = 0

0 + -1x = 0 + 7

-1x = 0 + 7

Combine like terms: 0 + 7 = 7

-1x = 7

Divide each side by '-1'.

x = -7

Simplifying

x = -7

Subproblem 2

Set the factor '(6 + -1x)' equal to zero and attempt to solve:

Simplifying

6 + -1x = 0

Solving

6 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + -1x = 0 + -6

Combine like terms: 6 + -6 = 0

0 + -1x = 0 + -6

-1x = 0 + -6

Combine like terms: 0 + -6 = -6

-1x = -6

Divide each side by '-1'.

x = 6

Simplifying

x = 6

Solution

x = {-7, 6}

Step-by-step explanation:

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PLEASE HELP
Sholpan [36]
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2) Similarly, we have that the equation is x=3y^2 \\  \frac{1}{4p} =3. Thus, p=1/12. In this case, the parabola opens along the x-axis and the focus is at (1/12, 0). Also, the directrix is at x=-1/12. Hence the correct answer is B.
3) We are given that the parabola has a p of 9. Also, the focus lies along the y-axis, hence the parabola is opening along the y-axis. Finally, the focus is on the positive half, so the parabola is opening upwards. The equation for this case is y=y=\frac{1}{4p} x^2= \frac{1}{36 } x^2.
4) Similarly as above. The directrix is superfluous, we only need the p-value. THe same comments about the parabola apply and if we substitute p=8 in the formula: y= \frac{1}{4p} x^2 we get y=\frac{1}{32} x^2.
5) This is somewhat different, even though we do not need the directrix again. The focus lies on the x-axis, thus the parabola opens in this direction. The focus lies on the positive part of the axis, thus the parabola opens to the right. We also are given p=7. Hence, the equation we need is of the formx= \frac{1}{4p} y^2. Substituting p=7, we get x= \frac{1}{28} y^2.
6) The equation of a prabola with a vertex at (0,0) is of the form y=-ax^2. The minus sign is needed since the parabola is downwards. Since we are given anothe point, we can calculate a. We have to take y=-74 and x=14 feet (since left to right is 28, we need to take half). -a= \frac{y}{x^2} = \frac{-74}{14^2} =-0.378. Thus a=0.378. Hence the correct expressions is y=-0.378*x^2
7 0
3 years ago
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Dada a Matriz A= [1 -2 1 ][-3 1 4] [0 6 8] , escreva uma matriz B diferente de A, tal que detA =detB.
Mariulka [41]

Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.

\mathbf A=\begin{bmatrix}1&-2&1\\-3&1&4\\0&6&8\end{bmatrix}

\mathbf B=\mathbf A^\top=\begin{bmatrix}1&-3&0\\-2&1&6\\1&4&8\end{bmatrix}

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4 years ago
What is the value of d?<br><br><br>Round your answer to the nearest tenth.
Sergeeva-Olga [200]

Answer:

11.9 mm

Step-by-step explanation:

We can find d by applying the cosine rules.

d²  = 21² + 27² - 2(21)(27) cos (25)

d²  = 441 + 729 - 1027.75

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3 years ago
How can you use rates to determine wheather a situation is a proportional relationship
svp [43]

<em>If the rate is a constant, the relationship is proportional.</em> (The rate is the constant of porportionality.)

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For two or more points on the function curve, divide the dependent variable value by the independent one. If you get the same result in every case, the relationship is porportional.

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<em>Note</em>

For some non-proportional relationships, it is possible to find points on the graph that will pass the above test. If you suspect the relationship is actually not one of proportionality, try more points. Check also to make sure that (0, 0) is on the curve.

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3 years ago
For each pair of triangles,tell:(a) are they congruent(b)write the triangle congruency statement.(c) Give the postulate that mak
pychu [463]
All right...before we begin, let's lay some ground rules about the postulate your teacher asks for in every problem. <em>If you already know what they are, skip this paragraph...</em>

A postulate is a statement that claims how the triangles are congruent from looking at the paper. For example, on number 2 we have three sides of the triangle so we would use the postulate SSS (side, side, side). However, number one we would use SAS (side, angle, side) because we see the angle square showing it is a 90-degree angle.
Let's begin! (I haven't done triangles in a while so I apologize in advance if some of my answers might be incorrect on the congruent (yes or no) part of it.)

1.
A) From a visual perspective, we can see the triangles are congruent.
B) ABE = CDE because they are the corresponding points.
C) We can use SAS for the postulate.

2.
A) Yes, they are congruent.
B) OLE = OVE
C) We can use SSS for their postulate.

3.
A) Yes, they are congruent.
B) AWT = ERT
C) We can use SAS for the postulate.

4.
A) I believe the triangles are congruent. You might want to check me on that.
B) GFE = FGH
C) SSS

5.
A) They are congruent because if IH bisects it, it is directly in the middle. So, we know that WH = HS and IH = IH (duh.) and their angles match.
B) WHI = SHI
C) SAS

6.
A) This one is intriguing because it would state above the shape "LE bisects LGUE." I'm going to take that it isn't exactly in the middle, but I am still going to say it is congruent.
B) LGE = EUL
C) ASA

7.
A) Yes, they are definitely congruent.
B) RTU = TRS
C) SSS (We have nothing that indicates angles.)

8.
A) Yes, they are congruent.
B) YWV = VZY
C) We can use SAS. (Might want to check that one.)

9.
A) I would say this one is NOT congruent.
B) There are only two points. One way is HT = MA
C) They are not congruent, you can not use a postulate. However, if you teacher insists on putting one, I would use SAS.

Once again, I would be careful about my answers. I haven't worked with triangles in a few years. If my math is incorrect, or I didn't give the answer you were looking for, please let me know. However, if my math is on point, please consider marking as <em>Brainliest</em>.

Have a good one.
God Bless.
7 0
4 years ago
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